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API Ajax结构化(API Ajax structuring)

我的目标:实施搜索功能,以显示从USDA NDB API中提取的营养数据。

状态:部分成功

问题是:美国农业部收购的物品有点令人讨厌。 推荐这个截图: http ://imgur.com/a/gOKdk比萨有第一个关键值的水和牛奶有能量。

我的问题:

如果我想获得所有搜索的能量,我将如何构建我的ajax调用?

$.ajax({
        type: 'GET',
        async: false,
        url: 'http://api.nal.usda.gov/ndb/reports/?ndbno=' + ndbno[0] + '&type=b&format=json&api_key=',
        success: function(results) {
            food0 = results.report.food;
            console.log(food0);
            $("#jsGrid-nutrition").jsGrid("insertItem", {
                name: food0.name,
                kCal: food0.nutrients[1].measures[0].value,
                servingSize: food0.nutrients[1].measures[0].label,
                quantity: food0.nutrients[1].measures[0].qty,
                carbs: food0.nutrients[4].value + food0.nutrients[4].unit,
                fats: food0.nutrients[3].value + food0.nutrients[3].unit,
                saturatedFats: food0.nutrients[3].value + food0.nutrients[3].unit,
                protein: food0.nutrients[24].value + food0.nutrients[24].unit
            });

My goal: Implement a search function to show nutritional data pulled from USDA NDB API.

Status: Partial Success

The problem: USDA stuctured the object returned somewhat obnoxious. Referincing this screenshot: http://imgur.com/a/gOKdk Pizza has water at the first key value and Milk has energy.

My Question:

If I want to obtain the energy for example for all searches, how would I structure my ajax call?

$.ajax({
        type: 'GET',
        async: false,
        url: 'http://api.nal.usda.gov/ndb/reports/?ndbno=' + ndbno[0] + '&type=b&format=json&api_key=',
        success: function(results) {
            food0 = results.report.food;
            console.log(food0);
            $("#jsGrid-nutrition").jsGrid("insertItem", {
                name: food0.name,
                kCal: food0.nutrients[1].measures[0].value,
                servingSize: food0.nutrients[1].measures[0].label,
                quantity: food0.nutrients[1].measures[0].qty,
                carbs: food0.nutrients[4].value + food0.nutrients[4].unit,
                fats: food0.nutrients[3].value + food0.nutrients[3].unit,
                saturatedFats: food0.nutrients[3].value + food0.nutrients[3].unit,
                protein: food0.nutrients[24].value + food0.nutrients[24].unit
            });

原文:https://stackoverflow.com/questions/41960493
更新时间:2022-06-19 12:06

最满意答案

使用afterClose回调...


Use the afterClose callback...

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