基于ajax的网站的PHP爬虫？(php crawler for ajax based websites?)

 你的代码奇怪的主要原因是你所有的西装词典（ S ， H ， D和C ）都引用了同一个字典。 如果您希望它们指向不同的引用（例如S, H, D, C = {}, {}, {}, {} ） S, H, D, C = {}, {}, {}, {}则需要单独初始化它们。 
 
 话虽如此， eval （几乎）绝不是解决方案。 在你的情况下，我会做类似的事情： 
 
keys = list('23456789TJQKA')
values = range (13)
suitDict = {}
for key,value in zip(keys, values):
    suitDict[key] = value
dealList = 'AQJT5.KQ.8.KQT95 3.A765.QT743.843 974.T93.J92.AJ62 K862.J842.AK65.7'.split()
players = list('NESW')
suits = {"S": {}, "H": {}, "D": {}, "C": {}}
playerHand = {}
for player,hand in zip(players,dealList):
    playerHand[player] = hand
    print player,hand
        for suit,cards in zip(suits,playerHand[player].split('.')):
            print "SC:",suit,cards
            for card in cards:
                suits[suit][suitDict[card]] = player
                print "card",card,"Suit",suit,"X",suits[suit],"card",suitDict[card],"player",player
 
 话虽如此，我认为你的案件过于复杂...... 

Your code oddity is mainly caused by the fact that all your suit dictionaries (S, H, D and C) are referencing the same dictionary. You need to initialize them separately if you want them to point to a different reference (e.g. S, H, D, C = {}, {}, {}, {}).
 
That being said, eval is (almost) never a solution. In your case, I'd do something like:
 
keys = list('23456789TJQKA')
values = range (13)
suitDict = {}
for key,value in zip(keys, values):
    suitDict[key] = value
dealList = 'AQJT5.KQ.8.KQT95 3.A765.QT743.843 974.T93.J92.AJ62 K862.J842.AK65.7'.split()
players = list('NESW')
suits = {"S": {}, "H": {}, "D": {}, "C": {}}
playerHand = {}
for player,hand in zip(players,dealList):
    playerHand[player] = hand
    print player,hand
        for suit,cards in zip(suits,playerHand[player].split('.')):
            print "SC:",suit,cards
            for card in cards:
                suits[suit][suitDict[card]] = player
                print "card",card,"Suit",suit,"X",suits[suit],"card",suitDict[card],"player",player
 
That being said, I think you're over-complicating your case...