使用AJAX,PHP和Javascript自动填充输入文本框(auto fill input text boxes using AJAX and PHP and Javascript)
我有一个选择框,其中包含使用数据库(phpmyadmin)中的数据生成的选项,数据库如下所示:
Columns: locationID - address - postalcode - place
在选择框之后我有一些输入字段,首先是标准的一些占位符。
我的想法是,如果我选择一个选项,将从数据库中生成并填充字段(
contactperson
字段除外,这将保持手动)。为此,我尝试使用AJAX。
我已经做了这个:
test.php :
<?php //Query the database for the results we want $query1 = $conn->query("SELECT * FROM deliveryaddress"); //Create an array of objects for each returned row while($locationArray[] = $query1->fetch_object()); //Remove the blank entry at end of array array_pop($locationArray); ?> <script> $(document).on("change","#select-box").function(){ var id = $(this).val(); $.ajax({ url : "locationAjax.php", data : {"id":id}, type : "POST", dataType : "HTML", success : function(data){ // here you can write code to asign the values to text boxes. $(".wrapperDiv").html(data); } }); }); </script> <div class="wrapperDiv"> <label for="locationLabel">Locatie</label> <select name="locations" id="locationSelectBox" > <option>Locatie</option> <?php foreach ($locationArray as $option) : ?> <option value="<?php echo $option->locationID; ?>"><?php echo $option->locationID; ?></option> <?php endforeach; ?> </select> <label for="address" style="float:left;">Straat/No</label> <input type="text" name="address" id="address" placeholder="Straatnaam en nummer" /> <label for="postalCode">Postcode</label> <input type="text" name="postalCode" id="postalCode" placeholder="Postcode" /> <label for="place">Plaats</label> <input type="text" name="place" id="place" placeholder="Plaats" /> <label for="contactPerson">Contact</label> <input type="text" name="contactPerson" id="contactPerson" placeholder="Contactpersoon" /> </div>
locationAjax.php :
<?php require_once('dbconnection.php'); $locationID = $_POST['id']; $sql = "SELECT * FROM deliveryaddress where id = $locationID"; $result = mysqli_query($conn, $sql); ?> <?php while ($row = mysqli_fetch_assoc($result)) { ?> <input type="text" name="name" value="<?= $row['address'] ?>" /> <input type="text" name="name" value="<?= $row['postalcode'] ?>" /> <input type="text" name="name" value="<?= $row['place'] ?>" /> } ?>
不幸的是,它不起作用。
I have a selectbox with options generated with data from a database(phpmyadmin) the database looks like this:
Columns: locationID - address - postalcode - place
After the select box I have some input fields, at first standard with some placeholders.
The idea is that if I select an option that the fields will be generated and filled from the database (except the
contactperson
field, this will stay manual)..For this I try to use AJAX.
I have already made this:
test.php:
<?php //Query the database for the results we want $query1 = $conn->query("SELECT * FROM deliveryaddress"); //Create an array of objects for each returned row while($locationArray[] = $query1->fetch_object()); //Remove the blank entry at end of array array_pop($locationArray); ?> <script> $(document).on("change","#select-box").function(){ var id = $(this).val(); $.ajax({ url : "locationAjax.php", data : {"id":id}, type : "POST", dataType : "HTML", success : function(data){ // here you can write code to asign the values to text boxes. $(".wrapperDiv").html(data); } }); }); </script> <div class="wrapperDiv"> <label for="locationLabel">Locatie</label> <select name="locations" id="locationSelectBox" > <option>Locatie</option> <?php foreach ($locationArray as $option) : ?> <option value="<?php echo $option->locationID; ?>"><?php echo $option->locationID; ?></option> <?php endforeach; ?> </select> <label for="address" style="float:left;">Straat/No</label> <input type="text" name="address" id="address" placeholder="Straatnaam en nummer" /> <label for="postalCode">Postcode</label> <input type="text" name="postalCode" id="postalCode" placeholder="Postcode" /> <label for="place">Plaats</label> <input type="text" name="place" id="place" placeholder="Plaats" /> <label for="contactPerson">Contact</label> <input type="text" name="contactPerson" id="contactPerson" placeholder="Contactpersoon" /> </div>
locationAjax.php:
<?php require_once('dbconnection.php'); $locationID = $_POST['id']; $sql = "SELECT * FROM deliveryaddress where id = $locationID"; $result = mysqli_query($conn, $sql); ?> <?php while ($row = mysqli_fetch_assoc($result)) { ?> <input type="text" name="name" value="<?= $row['address'] ?>" /> <input type="text" name="name" value="<?= $row['postalcode'] ?>" /> <input type="text" name="name" value="<?= $row['place'] ?>" /> } ?>
unfortunatly, it doesn't work.
原文:https://stackoverflow.com/questions/32121152
最满意答案
如果
expiredRewardsArray
和rewardsArray
是对象数组,那么您需要使用它们的id
属性比较它们,而不是indexOf(_:)
。 原因是对象是引用类型,所以你可以有两个具有相同属性的不同对象,但如果它们不是同一个对象,indexOf(_:)
会将它们视为单独的实体。试试这个代码:
func rewardsMinusExpired() { expiredRewardsArray = rewardManager.getExpiredRewards() rewardsArray = rewardsArray.filter { reward in let isExpired = expiredRewardsArray.contains { expiredReward in return expiredReward.id == reward.id } return !isExpired } }
If
expiredRewardsArray
andrewardsArray
are arrays of objects, then you'll need to compare the elements using theirid
property to compare them, rather thanindexOf(_:)
. The reason for this is that objects are reference types, so you can have two different objects with identical properties, but if they're not the same object,indexOf(_:)
will treat them as separate entities.Try this code instead:
func rewardsMinusExpired() { expiredRewardsArray = rewardManager.getExpiredRewards() rewardsArray = rewardsArray.filter { reward in let isExpired = expiredRewardsArray.contains { expiredReward in return expiredReward.id == reward.id } return !isExpired } }
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