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使用AJAX,PHP和Javascript自动填充输入文本框(auto fill input text boxes using AJAX and PHP and Javascript)

我有一个选择框,其中包含使用数据库(phpmyadmin)中的数据生成的选项,数据库如下所示:

Columns: locationID - address - postalcode - place

在选择框之后我有一些输入字段,首先是标准的一些占位符。

我的想法是,如果我选择一个选项,将从数据库中生成并填充字段( contactperson字段除外,这将保持手动)。

为此,我尝试使用AJAX。

我已经做了这个:

test.php

<?php
    //Query the database for the results we want
    $query1 = $conn->query("SELECT * FROM deliveryaddress");

    //Create an array of objects for each returned row
    while($locationArray[] = $query1->fetch_object());

    //Remove the blank entry at end of array
    array_pop($locationArray);
?>

<script>
    $(document).on("change","#select-box").function(){
        var id = $(this).val();
        $.ajax({
            url      : "locationAjax.php",
            data     : {"id":id},
            type     : "POST",
            dataType : "HTML",
            success  : function(data){
                // here you can write code to asign the values to text boxes.
                $(".wrapperDiv").html(data); 
            }
        });
    });
</script>

<div class="wrapperDiv">
    <label for="locationLabel">Locatie</label>
    <select name="locations" id="locationSelectBox" >
        <option>Locatie</option>
        <?php foreach ($locationArray as $option) : ?>
            <option value="<?php echo $option->locationID; ?>"><?php echo $option->locationID; ?></option>
        <?php endforeach; ?>
    </select>

    <label for="address" style="float:left;">Straat/No</label>
    <input type="text" name="address" id="address" placeholder="Straatnaam en nummer" />

    <label for="postalCode">Postcode</label>
    <input type="text" name="postalCode" id="postalCode" placeholder="Postcode" />

    <label for="place">Plaats</label>
    <input type="text" name="place" id="place" placeholder="Plaats" />

    <label for="contactPerson">Contact</label>
    <input type="text" name="contactPerson" id="contactPerson" placeholder="Contactpersoon" />
</div>

locationAjax.php

<?php
    require_once('dbconnection.php'); 
    $locationID = $_POST['id']; 
    $sql = "SELECT * FROM deliveryaddress where id = $locationID"; 
    $result = mysqli_query($conn, $sql); 
?> 
<?php while ($row = mysqli_fetch_assoc($result)) { ?> 
    <input type="text" name="name" value="<?= $row['address'] ?>" /> 
    <input type="text" name="name" value="<?= $row['postalcode'] ?>" /> 
    <input type="text" name="name" value="<?= $row['place'] ?>" /> 
} 
?>

不幸的是,它不起作用。


I have a selectbox with options generated with data from a database(phpmyadmin) the database looks like this:

Columns: locationID - address - postalcode - place

After the select box I have some input fields, at first standard with some placeholders.

The idea is that if I select an option that the fields will be generated and filled from the database (except the contactperson field, this will stay manual)..

For this I try to use AJAX.

I have already made this:

test.php:

<?php
    //Query the database for the results we want
    $query1 = $conn->query("SELECT * FROM deliveryaddress");

    //Create an array of objects for each returned row
    while($locationArray[] = $query1->fetch_object());

    //Remove the blank entry at end of array
    array_pop($locationArray);
?>

<script>
    $(document).on("change","#select-box").function(){
        var id = $(this).val();
        $.ajax({
            url      : "locationAjax.php",
            data     : {"id":id},
            type     : "POST",
            dataType : "HTML",
            success  : function(data){
                // here you can write code to asign the values to text boxes.
                $(".wrapperDiv").html(data); 
            }
        });
    });
</script>

<div class="wrapperDiv">
    <label for="locationLabel">Locatie</label>
    <select name="locations" id="locationSelectBox" >
        <option>Locatie</option>
        <?php foreach ($locationArray as $option) : ?>
            <option value="<?php echo $option->locationID; ?>"><?php echo $option->locationID; ?></option>
        <?php endforeach; ?>
    </select>

    <label for="address" style="float:left;">Straat/No</label>
    <input type="text" name="address" id="address" placeholder="Straatnaam en nummer" />

    <label for="postalCode">Postcode</label>
    <input type="text" name="postalCode" id="postalCode" placeholder="Postcode" />

    <label for="place">Plaats</label>
    <input type="text" name="place" id="place" placeholder="Plaats" />

    <label for="contactPerson">Contact</label>
    <input type="text" name="contactPerson" id="contactPerson" placeholder="Contactpersoon" />
</div>

locationAjax.php:

<?php
    require_once('dbconnection.php'); 
    $locationID = $_POST['id']; 
    $sql = "SELECT * FROM deliveryaddress where id = $locationID"; 
    $result = mysqli_query($conn, $sql); 
?> 
<?php while ($row = mysqli_fetch_assoc($result)) { ?> 
    <input type="text" name="name" value="<?= $row['address'] ?>" /> 
    <input type="text" name="name" value="<?= $row['postalcode'] ?>" /> 
    <input type="text" name="name" value="<?= $row['place'] ?>" /> 
} 
?>

unfortunatly, it doesn't work.


原文:https://stackoverflow.com/questions/32121152
更新时间:2021-12-14 08:12

最满意答案

如果expiredRewardsArrayrewardsArray是对象数组,那么您需要使用它们的id属性比较它们,而不是indexOf(_:) 。 原因是对象是引用类型,所以你可以有两个具有相同属性的不同对象,但如果它们不是同一个对象, indexOf(_:)会将它们视为单独的实体。

试试这个代码:

func rewardsMinusExpired() {
    expiredRewardsArray = rewardManager.getExpiredRewards()

    rewardsArray = rewardsArray.filter { reward in
        let isExpired = expiredRewardsArray.contains { expiredReward in
            return expiredReward.id == reward.id
        }
        return !isExpired
    }
}

If expiredRewardsArray and rewardsArray are arrays of objects, then you'll need to compare the elements using their id property to compare them, rather than indexOf(_:). The reason for this is that objects are reference types, so you can have two different objects with identical properties, but if they're not the same object, indexOf(_:) will treat them as separate entities.

Try this code instead:

func rewardsMinusExpired() {
    expiredRewardsArray = rewardManager.getExpiredRewards()

    rewardsArray = rewardsArray.filter { reward in
        let isExpired = expiredRewardsArray.contains { expiredReward in
            return expiredReward.id == reward.id
        }
        return !isExpired
    }
}

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