Ad hoc版本（Xcode 4.2，Lion）不会安装在4.2.1设备上(Ad hoc builds (Xcode 4.2, Lion) won't install on 4.2.1 devices)

 重要的是要注意$("div[id^='highc']")返回一个包含DOM元素集合的jQuery对象 （如果选择了任何内容）。 由于jQuery对象类似于数组， $("div[id^='highc']")[0]将返回jQuery对象中的第一个DOM元素。 
 
 您可能遇到的问题是您不能在本机DOM元素上使用jQuery方法（如.append() ）。 换句话说，如果你在jQuery对象的第一个DOM元素上链接.append()方法（即$("div[id^='highc']")[0].append(...) ），您将收到一条错误，指出.append()不是函数： 
 
 
 
 未捕获的TypeError： $(...)[0].append不是函数 
 
 
 由于.append()方法在jQuery对象上运行，因此可以使用.eq()方法来检索包含基于其索引的元素的jQuery对象。 
 
$("div[id^='highc']").eq(0).append('Text');
 
 或者，更丑陋的方法是使用$()包装DOM元素以返回jQuery对象： 
 
$($("div[id^='highc']")[0]).append('Text');
 
 
 边注： 
 
 在你的问题中你使用$("div[id^='highc'][0]")和$("div[id^='highc']")[0] 。 我假设这是一个错字，你的意思是后者，因为$("div[id^='highc'][0]")不会返回任何元素，因为元素可能没有[0]属性。 您可能尝试在选择器外部使用带有[0]的.append()方法。 

It's important to note that $("div[id^='highc']") returns a jQuery object that contains a collection of DOM elements (if anything is selected). Since jQuery objects are similar to arrays, $("div[id^='highc']")[0] will return the first DOM element in the jQuery object.
 
The issue that you're likely experiencing is that you can't use jQuery methods (like .append()) on native DOM elements. In other words, if you are chaining the .append() method on the first DOM element in the jQuery object (i.e., $("div[id^='highc']")[0].append(...)), you will receive an error stating that .append() is not a function:
 
 
 
Uncaught TypeError: $(...)[0].append is not a function
 
 
Since the .append() methods operates on a jQuery object, you could use the .eq() method in order to retrieve a jQuery object containing the element based on its index.
 
$("div[id^='highc']").eq(0).append('Text');
 
Alternatively, an uglier approach would be to wrap the DOM element with $() in order to return a jQuery object:
 
$($("div[id^='highc']")[0]).append('Text');
 
 
Side note:
 
In your question you used both $("div[id^='highc'][0]") and $("div[id^='highc']")[0]. I'm assuming it was a typo and you meant the latter since $("div[id^='highc'][0]") wouldn't return any elements due to the fact that the elements probably don't have a [0] attribute. You probably attempted to use the .append() method with [0] outside of the selector.