执行浅拷贝后如何管理内存?(How the memory will be managed after doing shallow copy?)
我试图了解内存管理概念,并开始从Apple文档和许多关于Objective-C内存管理的文章中挖掘。 当我开始从Apple文档搜索时,我被发送回对象复制和消息传递概念。
在阅读有关复制对象时,我遇到了一个问题,我试图找到解决方案,但未能得到满意的解决方案。 如果有人能帮助我,我们将感到荣幸。 问题是:
array1 = {obj1,obj2,obj3} array2 = {obj4,obj5,obj6} array2 = array1 -- Shallow Copy
与array2相关的内存发生了什么变化? 如果有泄漏怎么发布? 在ARC和NonARC环境中执行此类浅拷贝的更好做法是什么?
I was trying to understand memory management concept, and start digging from Apple docs and many articles regarding Memory management in Objective-C. When I start searching from Apple docs I was send back to object copying and messaging concept.
While reading about copying object I hit one question and I was trying to find the solution but fail to get satisfactory solution. It will be honor if someone will help me out. Question is:
array1 = {obj1,obj2,obj3} array2 = {obj4,obj5,obj6} array2 = array1 -- Shallow Copy
What happened to the memory which was associated with array2? How to release if there is a leak? What is better practice to perform such shallow copy in ARC and NonARC environment?
原文:https://stackoverflow.com/questions/36645157
最满意答案
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DECLARE @ThisYear VARCHAR(50) DECLARE @NextYear VARCHAR(50) SET @ThisYear = CAST(DATEPART(YYYY,GETDATE()) as varchar(20)) +'0731' --print @ThisYear SET @NextYear = CAST(DATEPART(YYYY,DATEADD(YYYY,1,GETDATE()))as varchar(20))+'1231' --print @Nextyear SELECT * FROM TABLE WHERE CAST(ClaimNo AS DATE) BETWEEN @ThisYear and @NextYear
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