首页 \ 问答 \ 如何转换Eigen :: Affine3f至Eigen :: Matrix4f(How to convert from Eigen::Affine3f to Eigen::Matrix4f)

如何转换Eigen :: Affine3f至Eigen :: Matrix4f(How to convert from Eigen::Affine3f to Eigen::Matrix4f)

我有两个问题。

  1. Eigen :: Affine3f和Eigen :: Matrix4f中表示的刚性变换是否相同?

  2. 我们如何从Eigen :: Affine3f转换为Eigen :: Matrix4f,反之亦然?

谢谢你的帮助!


I have two questions.

  1. Does the rigid transformation represented in Eigen::Affine3f and Eigen::Matrix4f will be the same ?

  2. How can we convert from Eigen::Affine3f to Eigen::Matrix4f and vice versa ?

Thanks for your help!


原文:https://stackoverflow.com/questions/23262476
更新时间:2023-01-09 19:01

最满意答案

我希望能够实现它,以便它可以用于已知且始终命名为相同ID1,ID2,Grp和任何数量的具有未知名称的其他数字列的数据框。

您可以先覆盖ID列,然后按它们分组:

DF %>% 
  group_by(Grp) %>% mutate_each(funs(. %>% unique %>% sort %>% toString), ID1, ID2) %>% 
  group_by(ID1, ID2, add=TRUE) %>% summarise_each(funs(sum))

# Source: local data frame [2 x 6]
# Groups: Grp, ID1 [?]
# 
#     Grp   ID1   ID2  Col1  Col2  Col3
#   (chr) (chr) (chr) (int) (int) (int)
# 1    G1  A, C  B, D     4     8    13
# 2    G2  E, G  F, h     9    11    15

我想你会想要在折叠成字符串之前进行统一和排序,所以我添加了这些步骤。


I would like to be able to implement it so that it would work for a data frame with known and always named the same ID1, ID2, Grp, and any number of additional numeric column with unknown names.

You can overwrite the ID columns first and then group by them as well:

DF %>% 
  group_by(Grp) %>% mutate_each(funs(. %>% unique %>% sort %>% toString), ID1, ID2) %>% 
  group_by(ID1, ID2, add=TRUE) %>% summarise_each(funs(sum))

# Source: local data frame [2 x 6]
# Groups: Grp, ID1 [?]
# 
#     Grp   ID1   ID2  Col1  Col2  Col3
#   (chr) (chr) (chr) (int) (int) (int)
# 1    G1  A, C  B, D     4     8    13
# 2    G2  E, G  F, h     9    11    15

I think you'll want to uniqify and sort before collapsing to a string, so I've added those steps.

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