找到没有它的二进制路径(Find path to binary without which)

 我所贡献的一个开源项目依赖于我想删除的项目，因为一些Linux发行版（如Fedora 20的云版本）默认不附带它，我相信强迫它安装，考虑到我们使用它是多么微不足道。 
 
 我们所做的就是找到Java二进制文件的路径，然后使用该信息设置$JAVA_HOME 。 
 
 有没有办法用Bash内置插件做到这一点？ 一般来说，如何在最小化依赖关系（如which ）的同时优雅地找到二进制文件？ 或者它是一个更好的调用只是使用which ，例如，如果唯一的选择是运行find $PATH中的目录，社区认为是非常不优雅？ 
 
 请注意，对于与之相关的事情，Google的效果极其低下。 

An Open Source project I contribute to has a dependency on which that I'd like to remove, as some Linux distros (like the cloud version of Fedora 20) don't ship with it by default, and I believe it's ugly to force its install, given how trivial our use of it is.
 
All we're doing is finding the path to the Java binary, then using that info to set $JAVA_HOME.
 
Is there a way to do that with Bash built-ins? In general, how can I somewhat-elegantly find a binary while minimizing dependencies (like which)? Or is it a better call to just use which, for example if the only alternative is to run find against directories in $PATH and the community believes that to be exceedingly inelegant?
 
Note that it's extremely ineffective to Google for which-related things. 

原文：https://stackoverflow.com/questions/23960511