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如何找到Spring Data JPA和Spring版本的正确jar文件(How to find correct jar file of Spring Data JPA and Spring version)

 我正在使用Spring MVC和Spring Data JPA，并面对jar版本的异常。  
 这是我的朋友：  
<properties>
    <spring.version>4.2.4.RELEASE</spring.version>
    <hibernate.version>4.3.8.Final</hibernate.version>
    <mysql.version>5.1.10</mysql.version>
    <junit-version>4.11</junit-version>
    <servlet-api-version>3.1.0</servlet-api-version>
    <spring-security-version>4.0.4.RELEASE</spring-security-version> 
    <spring-data-solr.verion>1.2.0.RELEASE</spring-data-solr.verion>         
    <springbatch.version>3.0.6.RELEASE</springbatch.version>
    <jsp-version>2.1</jsp-version>
    <jstl-version>1.2</jstl-version>
    <java.version>1.7</java.version>
    <liquibase.version>3.1.1</liquibase.version>
    <spring.data.jpa.version>1.10.3.RELEASE</spring.data.jpa.version>   
    <spring.social.version>1.1.0.RELEASE</spring.social.version>                        
</properties>
 
 这是我的班级：  
import org.springframework.data.jpa.repository.JpaRepository;
public interface RoleRepository extends JpaRepository<Role, Long> {

}
 
 我在Eclipse上收到一条错误警告消息：  
The type org.springframework.data.repository.query.QueryByExampleExecutor cannot be resolved. It is indirectly referenced from required .class files
 
 看起来我的Spring数据jpa jar版本不正确，但我不知道找到了正确的版本。 我的春天verion：4.2.4.RELEASE是最新的  
 如何解决这个错误？ 非常感谢 ！ 

I'm using Spring MVC and Spring Data JPA and facing with an exception of jar version.  
This is my pom: 
<properties>
    <spring.version>4.2.4.RELEASE</spring.version>
    <hibernate.version>4.3.8.Final</hibernate.version>
    <mysql.version>5.1.10</mysql.version>
    <junit-version>4.11</junit-version>
    <servlet-api-version>3.1.0</servlet-api-version>
    <spring-security-version>4.0.4.RELEASE</spring-security-version> 
    <spring-data-solr.verion>1.2.0.RELEASE</spring-data-solr.verion>         
    <springbatch.version>3.0.6.RELEASE</springbatch.version>
    <jsp-version>2.1</jsp-version>
    <jstl-version>1.2</jstl-version>
    <java.version>1.7</java.version>
    <liquibase.version>3.1.1</liquibase.version>
    <spring.data.jpa.version>1.10.3.RELEASE</spring.data.jpa.version>   
    <spring.social.version>1.1.0.RELEASE</spring.social.version>                        
</properties>
 
This is my class:  
import org.springframework.data.jpa.repository.JpaRepository;
public interface RoleRepository extends JpaRepository<Role, Long> {

}
 
I received an error warning on Eclipse with message: 
The type org.springframework.data.repository.query.QueryByExampleExecutor cannot be resolved. It is indirectly referenced from required .class files
 
It seem my Spring data jpa jar version is incorrect, but I don't know find correct version. My Spring verion: 4.2.4.RELEASE is latest 
How to fix this error? Thank so much !

原文：https://stackoverflow.com/questions/43006156

更新时间：2023-10-17 15:10

最满意答案

 下面是生成的缩进更好的JavaScript：  
_(gameState.loot).pick(function(value, key) {
    return key !== "pickUpAnimations";
}).filter(
    (function(d) {
        return _.isArray(d);
    }).reduce((function(sum, d) {
        return sum.concat(d);
    }))
);
 
 正如你所看到的， .filter (...和.filter(...不一样，两种可能的修正：  
 
  删除方法名称和开头括号之间的空格： 
_(gameState.loot)
    .pick((value, key) -> key isnt "pickUpAnimations")
    .filter((d) -> _.isArray (d))
    .reduce((sum, d) -> sum.concat (d))
 
  完全删除括号： 
_(gameState.loot)
    .pick (value, key) -> key isnt "pickUpAnimations"
    .filter (d) -> _.isArray (d)
    .reduce (sum, d) -> sum.concat (d)
 
 
 你也可以去掉调用_.isArray的匿名函数：  
    _(gameState.loot)
        .pick (value, key) -> key isnt "pickUpAnimations"
        .filter _.isArray
        .reduce (sum, d) -> sum.concat (d)

Here's the generated JavaScript with better indentation: 
_(gameState.loot).pick(function(value, key) {
    return key !== "pickUpAnimations";
}).filter(
    (function(d) {
        return _.isArray(d);
    }).reduce((function(sum, d) {
        return sum.concat(d);
    }))
);
 
As you can see, .filter (... and .filter(... are not the same. Two possible fixes: 
 
 Remove the whitespace between the method names and the opening parentheses:
 _(gameState.loot)
    .pick((value, key) -> key isnt "pickUpAnimations")
    .filter((d) -> _.isArray (d))
    .reduce((sum, d) -> sum.concat (d))
 
 Remove the parentheses entirely:
 _(gameState.loot)
    .pick (value, key) -> key isnt "pickUpAnimations"
    .filter (d) -> _.isArray (d)
    .reduce (sum, d) -> sum.concat (d)
 
 
You can also get rid of the anonymous function calling _.isArray: 
    _(gameState.loot)
        .pick (value, key) -> key isnt "pickUpAnimations"
        .filter _.isArray
        .reduce (sum, d) -> sum.concat (d)

如何找到Spring Data JPA和Spring版本的正确jar文件(How to find correct jar file of Spring Data JPA and Spring version)

最满意答案

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