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运营顺序(Order of Operations)

 我需要帮助解决输出代码问题。 很抱歉我需要帮助修复hI的输出。 可以找到两个输入文件（即将发布）  
 请询问您是否需要输出的内容或解决hI的公式（我只能发布两个链接。）。  
import java.util.Scanner;
import java.io.File;
import java.io.IOException;

public class HeatIndex
{
    public static void main(String[] args) throws IOException
    {


    String location = "Key West, Florida";
    File fileNameTemp = new File("KeyWestTemp.txt");
    File fileNameHumid = new File("KeyWestHumid.txt");

    Scanner inFileTemp = new Scanner(fileNameTemp);
    Scanner inFileHumid = new Scanner(fileNameHumid);

    String [] month = {"January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "Novermber", "December"};
    int length = month.length;
    double [] temperature = new double[length];
    int [] humidity = new int[length];
    double [] hI = new double[length];


    //INPUT - read in data for temp and humidity from files

    int n = 0; //index value for arrays
    while( inFileTemp.hasNextDouble() )
    {
        temperature[n] = inFileTemp.nextDouble();
        //System.out.println (temperature[n]); //debug statement - uncomment to see values assignned to temperature
        n++;
    }
    inFileTemp.close();


    n = 0; //reset index to 0
    while (inFileHumid.hasNextDouble())
    {
            humidity[n] = inFileHumid.nextInt();
            //System.out.println (humidity[n]);  //debug statement - uncomment to see values assignned to humidity
            n++;
    }
    inFileHumid.close();

    //PROCESSING - calculate Heat Index if needed- see lecture notes for details, formula is incomplete

    double t = 0.0;
    int h = 0;

    for(n = 0; n < hI.length; n++)
    {
        if( temperature[n] >= 80.0  ) //determine if HI should be calculated, complete the condition based on Lecture notes
        {
            t = temperature[n];
            h = humidity[n];

            hI[n] = -42.379 + 2.04901523*t+ 10.1433312*h- 0.22475541*t*h- 0.000683783*(t*t)- 0.005481717* (h*h)+ 0.000122874*(h*h)*t+ 0.000085282*t*(h*h)- 0.000000199*(t*t)*(h*h);
}

I need help with solving my problem of output code. Sorry for the big chunk of code I need help fixing the output for hI. The two input files can be found (soon to be posted) 
Please ask if you need what the output looks like or the formula for solving hI ( I can only post two links.). 
import java.util.Scanner;
import java.io.File;
import java.io.IOException;

public class HeatIndex
{
    public static void main(String[] args) throws IOException
    {


    String location = "Key West, Florida";
    File fileNameTemp = new File("KeyWestTemp.txt");
    File fileNameHumid = new File("KeyWestHumid.txt");

    Scanner inFileTemp = new Scanner(fileNameTemp);
    Scanner inFileHumid = new Scanner(fileNameHumid);

    String [] month = {"January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "Novermber", "December"};
    int length = month.length;
    double [] temperature = new double[length];
    int [] humidity = new int[length];
    double [] hI = new double[length];


    //INPUT - read in data for temp and humidity from files

    int n = 0; //index value for arrays
    while( inFileTemp.hasNextDouble() )
    {
        temperature[n] = inFileTemp.nextDouble();
        //System.out.println (temperature[n]); //debug statement - uncomment to see values assignned to temperature
        n++;
    }
    inFileTemp.close();


    n = 0; //reset index to 0
    while (inFileHumid.hasNextDouble())
    {
            humidity[n] = inFileHumid.nextInt();
            //System.out.println (humidity[n]);  //debug statement - uncomment to see values assignned to humidity
            n++;
    }
    inFileHumid.close();

    //PROCESSING - calculate Heat Index if needed- see lecture notes for details, formula is incomplete

    double t = 0.0;
    int h = 0;

    for(n = 0; n < hI.length; n++)
    {
        if( temperature[n] >= 80.0  ) //determine if HI should be calculated, complete the condition based on Lecture notes
        {
            t = temperature[n];
            h = humidity[n];

            hI[n] = -42.379 + 2.04901523*t+ 10.1433312*h- 0.22475541*t*h- 0.000683783*(t*t)- 0.005481717* (h*h)+ 0.000122874*(h*h)*t+ 0.000085282*t*(h*h)- 0.000000199*(t*t)*(h*h);
}

原文：https://stackoverflow.com/questions/20156697

更新时间：2022-07-26 14:07

最满意答案

 您可以使用getter和setter作为实现此目的的一种方法。  
 
// our constructor function
function Color(r, g, b) {
    return {
        get red() {
            return r;
        },

        set red(value) {
            // let's make sure we get a number here
            if ( typeof value === 'number' && !isNaN(value) ) {
                // check the range
                if (value < 0) {
                    r = 0;
                } else if (value > 255) {
                    r = 255;
                } else {
                    r = value;
                }
            } else {
                // this gets set if they don't pass a number
                r = 255;
            }
        }
        // other color methods here
    };
}

// --------------------

var red = new Color(255, 0, 0);

alert(red.red); // 255

red.red -= 55;  // assignment within range, success

alert(red.red); // 200

red.red -= 999; // assignment out of range, failure

alert(red.red); // 0

red.red += 999; // assignment out of range, failure

alert(red.red); // 255
 
 
 jsFiddle示例 

You can use getters and setters as one way to achieve this. 
 
// our constructor function
function Color(r, g, b) {
    return {
        get red() {
            return r;
        },

        set red(value) {
            // let's make sure we get a number here
            if ( typeof value === 'number' && !isNaN(value) ) {
                // check the range
                if (value < 0) {
                    r = 0;
                } else if (value > 255) {
                    r = 255;
                } else {
                    r = value;
                }
            } else {
                // this gets set if they don't pass a number
                r = 255;
            }
        }
        // other color methods here
    };
}

// --------------------

var red = new Color(255, 0, 0);

alert(red.red); // 255

red.red -= 55;  // assignment within range, success

alert(red.red); // 200

red.red -= 999; // assignment out of range, failure

alert(red.red); // 0

red.red += 999; // assignment out of range, failure

alert(red.red); // 255
 
 
jsFiddle example

运营顺序(Order of Operations)

最满意答案

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