首页 \ 问答 \ 原型未按预期工作(Prototype is not working as expected)

原型未按预期工作(Prototype is not working as expected)

我使用下面的代码来学习JS原型以及如何使用对象,(在我在网上阅读它之后我刚接触到JS ...)我想创建一个其他类可以使用和扩展的根对象确定如果我这样做...目前我在声音上有错误(无法设置未定义的属性'声音',任何想法我做错了或者有更好的方法来写它,(对我来说这是第三个)草案...:) )

var obj = function(name){

    this.name  = name;
};

obj.prototype.getName = function(){
    return this.name;
}

var person = new obj("Bill");

console.log(person.getName());


var animal = new obj();

animal.prototype.sound = function(sound){
    console.log(sound)
}


var dog = new animal();


dog.sound("wof");

Im using the following code in order to learn JS prototype and how to works with objects,(after I read about it on the net Im new to JS...)I want to create a root object that other class can use and extend not sure if I do that right...currently I've error at the sound (Cannot set property 'sound' of undefined),any idea what Im doing wrong or maybe there is better way to write it,(for me it's the third draft...:) )

var obj = function(name){

    this.name  = name;
};

obj.prototype.getName = function(){
    return this.name;
}

var person = new obj("Bill");

console.log(person.getName());


var animal = new obj();

animal.prototype.sound = function(sound){
    console.log(sound)
}


var dog = new animal();


dog.sound("wof");

原文:https://stackoverflow.com/questions/27173578
更新时间:2022-06-24 16:06

最满意答案

我提到了这个链接Android Permissions

我能够解决自己的问题,因为我从未进入清单并在此添加此行

      <uses-permission android:name="android.permission.GET_ACCOUNTS"/>

添加此行会阻止应用程序崩溃,因为它能够找到帐户并存储它们,然后继续连接而没有该行它将无法获得帐户并且将在代码的第一部分失败获取帐户代码因此导致应用程序崩溃。


I referred to this link Android Permissions

I was able to solve my own question because I never went into the manifest and added this line here

      <uses-permission android:name="android.permission.GET_ACCOUNTS"/>

Adding this line stops the application from crashing because its able to locate the account and store them and then continue to connect without that line it wont get the account and will fail on the first part of your code Get Account code therefore causing your application to crash.

相关问答

更多

相关文章

更多

最新问答

更多
  • 获取MVC 4使用的DisplayMode后缀(Get the DisplayMode Suffix being used by MVC 4)
  • 如何通过引用返回对象?(How is returning an object by reference possible?)
  • 矩阵如何存储在内存中?(How are matrices stored in memory?)
  • 每个请求的Java新会话?(Java New Session For Each Request?)
  • css:浮动div中重叠的标题h1(css: overlapping headlines h1 in floated divs)
  • 无论图像如何,Caffe预测同一类(Caffe predicts same class regardless of image)
  • xcode语法颜色编码解释?(xcode syntax color coding explained?)
  • 在Access 2010 Runtime中使用Office 2000校对工具(Use Office 2000 proofing tools in Access 2010 Runtime)
  • 从单独的Web主机将图像传输到服务器上(Getting images onto server from separate web host)
  • 从旧版本复制文件并保留它们(旧/新版本)(Copy a file from old revision and keep both of them (old / new revision))
  • 西安哪有PLC可控制编程的培训
  • 在Entity Framework中选择基类(Select base class in Entity Framework)
  • 在Android中出现错误“数据集和渲染器应该不为null,并且应该具有相同数量的系列”(Error “Dataset and renderer should be not null and should have the same number of series” in Android)
  • 电脑二级VF有什么用
  • Datamapper Ruby如何添加Hook方法(Datamapper Ruby How to add Hook Method)
  • 金华英语角.
  • 手机软件如何制作
  • 用于Android webview中图像保存的上下文菜单(Context Menu for Image Saving in an Android webview)
  • 注意:未定义的偏移量:PHP(Notice: Undefined offset: PHP)
  • 如何读R中的大数据集[复制](How to read large dataset in R [duplicate])
  • Unity 5 Heighmap与地形宽度/地形长度的分辨率关系?(Unity 5 Heighmap Resolution relationship to terrain width / terrain length?)
  • 如何通知PipedOutputStream线程写入最后一个字节的PipedInputStream线程?(How to notify PipedInputStream thread that PipedOutputStream thread has written last byte?)
  • python的访问器方法有哪些
  • DeviceNetworkInformation:哪个是哪个?(DeviceNetworkInformation: Which is which?)
  • 在Ruby中对组合进行排序(Sorting a combination in Ruby)
  • 网站开发的流程?
  • 使用Zend Framework 2中的JOIN sql检索数据(Retrieve data using JOIN sql in Zend Framework 2)
  • 条带格式类型格式模式编号无法正常工作(Stripes format type format pattern number not working properly)
  • 透明度错误IE11(Transparency bug IE11)
  • linux的基本操作命令。。。