没有使用默认命名空间的XSL输出XML没有前缀？(XSL output XML with no prefix without using the default namespace?)

 我有一个XSL，我需要沿着这条线生成输出： 
 
<moo xmlns="http://api.example.com">
    <foo>1358944586848</foo>
    <bar>
        <a>1</a>
        <b>2</b>
        <c>3</c>
    </bar>
</moo>
 
 我可以这样做： 
 
<xsl:stylesheet version="2.0"
    xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
    xmlns="http://api.example.com">

    <xsl:template match="/">
        <xsl:element name="moo">
            <!-- and so on -->
 
 但是，我有点讨厌在我的xsl文件中使用xsl前缀，因为我觉得它让它变得很混乱。 无论如何，选择XPath很容易，因为你可以根据需要将xpath-default-namespace为你正在转换的任何东西。 但是就我所见，没有可用的element-default-namespace ，那么如何才能以良好的方式生成所需的输出呢？ 
 
 我知道我可以这样做： 
 
<stylesheet version="2.0"
    xmlns="http://www.w3.org/1999/XSL/Transform">

    <template match="/">
        <element name="moo" namespace="http://api.example.com">
            <!-- and so on -->
 
 但是我必须在我创建的每个元素上显式设置这个命名空间，否则它们最终将使用XSL命名空间。 那么是否有一种干净的方法来创建具有特定命名空间（没有前缀）的元素而不触及xsl文件的默认命名空间？ 
 
 
 更新： 
 
 想象也许namespace-alias可以做一些事情，但无法弄清楚如何使用它。 试过这个，但输出似乎没有任何差别： 
 
<stylesheet version="2.0"
    xmlns="http://www.w3.org/1999/XSL/Transform"
xmlns:out="http://api.example.com">

<namespace-alias stylesheet-prefix="out" result-prefix=""/>

    <template match="/">
        <element name="out:moo">
            <!-- and so on -->
 
 namespace-alias可能不是我认为的那样：p 
 
 我使用的最终解决方案，基于JLRishe的答案 
 
 除去-prefixes.xsl 
 
<?xml version="1.0" encoding="UTF-8"?>
<stylesheet version="2.0" xmlns="http://www.w3.org/1999/XSL/Transform">
    <template match="/">
        <variable name="result">
            <next-match />
        </variable>
        <apply-templates select="$result" mode="remove-prefixes" />
    </template>

    <template match="*" priority="1" mode="remove-prefixes">
        <element name="{local-name()}" namespace="{namespace-uri()}">
            <apply-templates select="@* | node()" mode="remove-prefixes" />
        </element>
    </template>
    <template match="@*|node()" mode="remove-prefixes">
        <copy>
            <apply-templates select="@* | node()" mode="remove-prefixes" />
        </copy>
    </template>

</stylesheet>
 
 subject.xsl 
 
<!-- snip -->
<import href="remove-prefixes.xsl" />
<!-- snip -->

I have an XSL where I need to generate output along the lines of this:
 
<moo xmlns="http://api.example.com">
    <foo>1358944586848</foo>
    <bar>
        <a>1</a>
        <b>2</b>
        <c>3</c>
    </bar>
</moo>
 
I could do it like this:
 
<xsl:stylesheet version="2.0"
    xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
    xmlns="http://api.example.com">

    <xsl:template match="/">
        <xsl:element name="moo">
            <!-- and so on -->
 
However, I kind of hate using the xsl prefix in my xsl files cause I feel it clutters it up a lot. Selecting with XPath is easy anyways since you can set xpath-default-namespace to whatever you're transforming from if needed. But there is no element-default-namespace available as far as I can see, so how can I generate the wanted output in a good way?
 
I know I can do this:
 
<stylesheet version="2.0"
    xmlns="http://www.w3.org/1999/XSL/Transform">

    <template match="/">
        <element name="moo" namespace="http://api.example.com">
            <!-- and so on -->
 
But then I have to set this namespace explicitly on every single element I create, or they will end up with the XSL namespace instead. So is there a clean way to create elements with a certain namespace (without a prefix) and not touching the default namespace of the xsl file?
 
 
Update:
 
Figured maybe namespace-alias could do something, but can't figure out how to use it. Tried this, but doesn't seem to make any difference in the output at all:
 
<stylesheet version="2.0"
    xmlns="http://www.w3.org/1999/XSL/Transform"
xmlns:out="http://api.example.com">

<namespace-alias stylesheet-prefix="out" result-prefix=""/>

    <template match="/">
        <element name="out:moo">
            <!-- and so on -->
 
The namespace-alias thing probably isn't doing what I think it is :p
 
The final solution I used, based on JLRishe's answer
 
remove-prefixes.xsl
 
<?xml version="1.0" encoding="UTF-8"?>
<stylesheet version="2.0" xmlns="http://www.w3.org/1999/XSL/Transform">
    <template match="/">
        <variable name="result">
            <next-match />
        </variable>
        <apply-templates select="$result" mode="remove-prefixes" />
    </template>

    <template match="*" priority="1" mode="remove-prefixes">
        <element name="{local-name()}" namespace="{namespace-uri()}">
            <apply-templates select="@* | node()" mode="remove-prefixes" />
        </element>
    </template>
    <template match="@*|node()" mode="remove-prefixes">
        <copy>
            <apply-templates select="@* | node()" mode="remove-prefixes" />
        </copy>
    </template>

</stylesheet>
 
subject.xsl
 
<!-- snip -->
<import href="remove-prefixes.xsl" />
<!-- snip -->

原文：https://stackoverflow.com/questions/14480173