有效地计算闰日(Efficiently calculate leap days)

 我使用以下函数计算两年间的闰天数： 
 
static int CountLeapDays(int startYear, int endYear) 
{
    int Days = 0;

    while (true)
    {
        if ((startYear % 4 == 0 && startYear % 100 != 0) || startYear % 400 == 0)
            Days++;
        if (startYear + 1 == endYear) break;
        startYear++;
    }

    return Days;
}
 
 有没有其他方法来写这个，所以它不需要循环？ 

Im using the following function to calculate the number of leap days between two years:
 
static int CountLeapDays(int startYear, int endYear) 
{
    int Days = 0;

    while (true)
    {
        if ((startYear % 4 == 0 && startYear % 100 != 0) || startYear % 400 == 0)
            Days++;
        if (startYear + 1 == endYear) break;
        startYear++;
    }

    return Days;
}
 
Is there another way to write this so it doesnt need to loop?

原文：https://stackoverflow.com/questions/14878356