用于循环步骤(For loop with step)

 我创建了一个python脚本，它可以根据指定的step函数遍历一系列值。 
 
#!/usr/bin/python

def mul(value, step): return value * step
def inc(value, step): return value + step
def step_range(start, end, step, func):
    while start <= end:
        yield start
        start = func(start, step)

def main():
    for x in step_range(1, 64, 2, mul): 
        print '%d, '%(x),
    print
    for x in step_range(0, 64, 8, inc): 
        print '%d, '%(x),

if __name__ == '__main__':
    main()
 
 输出： 
 
$ python test.py
1,  2,  4,  8,  16,  32,  64,
0,  8,  16,  24,  32,  40,  48,  56,  64,
 
 无论如何，我可以摆脱辅助功能，以便用户可以做这样的事情？ 
 
for x in step_range(1, 64, *2): 
    ...

def step_range(start, end, step):
    while start <= end:
        yield start
        start = start ?step?
 
 这个? 标志着我陷入困境......我看着operator模块，但我必须知道mul(a, b)两个参数并add(a, b)函数。 

I have created a python script that can loop over a range of values based on a specified step function.
 
#!/usr/bin/python

def mul(value, step): return value * step
def inc(value, step): return value + step
def step_range(start, end, step, func):
    while start <= end:
        yield start
        start = func(start, step)

def main():
    for x in step_range(1, 64, 2, mul): 
        print '%d, '%(x),
    print
    for x in step_range(0, 64, 8, inc): 
        print '%d, '%(x),

if __name__ == '__main__':
    main()
 
Output:
 
$ python test.py
1,  2,  4,  8,  16,  32,  64,
0,  8,  16,  24,  32,  40,  48,  56,  64,
 
Is there anyway I can get rid of the helper functions so that the user can do something like this?
 
for x in step_range(1, 64, *2): 
    ...

def step_range(start, end, step):
    while start <= end:
        yield start
        start = start ?step?
 
The ? marks where I am stumped... I looked into the operator module but I would have to know both parameters for the mul(a, b) and add(a, b) functions.

原文：https://stackoverflow.com/questions/19171507