异步与Visual Studio 2013（Windows8.1）和GCC 4.9（Ubuntu14.10）的不同行为(Different behavior of async with Visual Studio 2013(Windows8.1) and GCC 4.9(Ubuntu14.10))

 async在Windows VS和Linux g ++中具有不同的行为（实现）。 
 
 我用以下代码测试了它： 
 
void Func1(){sleep(1000*1000);}
void Func2(){sleep(1000*2);throw runtime_error("An expected exception");}


int main(int argc, char* argv[]){
  try{
    auto f1 = async(launch::async, Func1);
    auto f2 = async(launch::async, Func2);

    f2.get();//block here
    f1.get();
  }catch (exception& e){
    printf("exception: %s\n", e.what());
  }
  return 0;
}
 
 Func1在发射后会长时间睡眠。 
 
 Func2将抛出异常。 
 
 我的观察是： 
 
 
 
 在Windows中，异常立即传播，主线程（程序）将相应地捕获它。 
 
 
 在Linux中，异常被保持，并且程序在Func1中的休眠1000秒结束之前不会退出。 
 
 
 所以在Linux中有人知道，如何让程序立即捕获异常并退出程序？ 

async has different behavior(implementation) in Windows VS and Linux g++.
 
I tested it with the following code:
 
void Func1(){sleep(1000*1000);}
void Func2(){sleep(1000*2);throw runtime_error("An expected exception");}


int main(int argc, char* argv[]){
  try{
    auto f1 = async(launch::async, Func1);
    auto f2 = async(launch::async, Func2);

    f2.get();//block here
    f1.get();
  }catch (exception& e){
    printf("exception: %s\n", e.what());
  }
  return 0;
}
 
Func1 sleeps for a long time after launch.
 
Func2 is to throw an exception.
 
My observation is:
 
 
 
In Windows, the exception is propagated immediately and the main thread(program) will catch it exit accordingly.
 
 
In Linux, the exception is held on and the program doesn't exit until the sleep 1000 seconds in Func1 is over.
 
 
So does anybody know in Linux, how to make the program catch the exception immediately and exit the program??

原文：https://stackoverflow.com/questions/30698207