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使用XStream读取XML(Read XML using XStream)

 如何编写java类来读取这个XMl文件  
<Response> 
<Models Make="SAMSUNG"> 
        <ModelNo>AB0-12343</ModelNo> 
        <ModelNo>BB1232222</ModelNo> 
    </Models>
     &t;Models Make="PANASONIC"> 
        <ModelNo>AB0-12343</ModelNo>
        <ModelNo>BB1232222</ModelNo> 
    </Models> 
</Response>
 
 我试过这样的  
@XStreamAlias("Response")
public class SL_LookupModelsResponse  {
    private ArrayList<Models> Models;

    public ArrayList<Models> getModels() {
        return Models;
    }

    public void setModels(ArrayList<Models> models) {
        Models = models;
    }

    @Override
    public String toString() {
        return "SL_LookupModelsResponse [Models=" + Models + "]";
    }

    @XStreamAlias("Models")
    class Models{
        private ArrayList<String> ModelNo;

        @XStreamAsAttribute  
        private String Make;  

        public ArrayList<String> getModelNos() {
            return ModelNo;
        }

        public void setModelNos(ArrayList<String> ModelNo) {
            this.ModelNo = ModelNo;
        }

        public String getMake() {  
            return Make;  
        }  

        public void setMake(String make) {  
            this.Make = make;  
        }  

        @Override
        public String toString() {
            return "Models [ModelNo=" + ModelNo + "Make="+ Make +"]";
        }

    }
  }
 
 但我得到这个错误  
Exception in thread "main" com.thoughtworks.xstream.converters.ConversionException: ModelNo : ModelNo
---- Debugging information ----
message             : ModelNo
cause-exception     : com.thoughtworks.xstream.mapper.CannotResolveClassException
cause-message       : ModelNo
class               : java.util.ArrayList
required-type       : java.util.ArrayList
converter-type      : com.thoughtworks.xstream.converters.collections.CollectionConverter
path                : /Response/Models/ModelNo
class[1]            : com.samples.SL_LookupModelsResponse
converter-type[1]   : com.thoughtworks.xstream.converters.reflection.ReflectionConverter
version             : null
 
 请帮我解决这个问题......  
 谢谢.. 

How to write java class to read this XMl file 
<Response> 
<Models Make="SAMSUNG"> 
        <ModelNo>AB0-12343</ModelNo> 
        <ModelNo>BB1232222</ModelNo> 
    </Models>
     <Models Make="PANASONIC"> 
        <ModelNo>AB0-12343</ModelNo>
        <ModelNo>BB1232222</ModelNo> 
    </Models> 
</Response>
 
I tried like this  
@XStreamAlias("Response")
public class SL_LookupModelsResponse  {
    private ArrayList<Models> Models;

    public ArrayList<Models> getModels() {
        return Models;
    }

    public void setModels(ArrayList<Models> models) {
        Models = models;
    }

    @Override
    public String toString() {
        return "SL_LookupModelsResponse [Models=" + Models + "]";
    }

    @XStreamAlias("Models")
    class Models{
        private ArrayList<String> ModelNo;

        @XStreamAsAttribute  
        private String Make;  

        public ArrayList<String> getModelNos() {
            return ModelNo;
        }

        public void setModelNos(ArrayList<String> ModelNo) {
            this.ModelNo = ModelNo;
        }

        public String getMake() {  
            return Make;  
        }  

        public void setMake(String make) {  
            this.Make = make;  
        }  

        @Override
        public String toString() {
            return "Models [ModelNo=" + ModelNo + "Make="+ Make +"]";
        }

    }
  }
 
But Im getting this error 
Exception in thread "main" com.thoughtworks.xstream.converters.ConversionException: ModelNo : ModelNo
---- Debugging information ----
message             : ModelNo
cause-exception     : com.thoughtworks.xstream.mapper.CannotResolveClassException
cause-message       : ModelNo
class               : java.util.ArrayList
required-type       : java.util.ArrayList
converter-type      : com.thoughtworks.xstream.converters.collections.CollectionConverter
path                : /Response/Models/ModelNo
class[1]            : com.samples.SL_LookupModelsResponse
converter-type[1]   : com.thoughtworks.xstream.converters.reflection.ReflectionConverter
version             : null
 
Please help me on how to solve this...  
Thank you..

原文：https://stackoverflow.com/questions/18610197

更新时间：2022-10-11 18:10

最满意答案

 这很有效，但它非常不直观。 赋值给你的属性（实际上是一个索引器）必须包含某种布尔值，它会被忽略和丢弃：  
Attribute a = new Attribute();
a["test"] = true;                 // Adds "test" as expected -- but WTF does the true mean?
a["foo"] = false;                 // Adds "foo" -- the false means nothing
Console.Out.WriteLine(a["test"]); // returns true
 
 所以是的，你可以做到这一点。 但这是一个糟糕的主意，因为没有人维护代码就会知道发生了什么。 那个悬而未决的布尔看起来像它有某种意义，但它不; 它违反了最小惊讶原则时，分配true与分配false相同的事情！ 更不用说，您作为“索引”传入的价值实际上并不是任何东西的索引。 这是合法的，但是以与预期目的完全不同的方式使用语法。  
 诚实地说，直接访问List<string>并调用其现有的Contains()和Add()方法会更好。 

This works, but it's horrendously counter-intuitive. Assignments to your property (which is actually an indexer) would have to contain some kind of Boolean value, which gets ignored and thrown away: 
Attribute a = new Attribute();
a["test"] = true;                 // Adds "test" as expected -- but WTF does the true mean?
a["foo"] = false;                 // Adds "foo" -- the false means nothing
Console.Out.WriteLine(a["test"]); // returns true
 
So yes, you can do this. But it's a bad idea, because no one maintaining the code will have a clue what's going on. That dangling Boolean looks like it has some kind of meaning, but it doesn't; it violates the Principle of Least Astonishment when assigning true does the same thing as assigning false! Not to mention, the value you pass in as an "index" really isn't an index into anything at all. It's legal, but using syntax in a completely different way from what it's intended for. 
In all honesty you'd be better served just accessing the List<string> directly and calling its existing Contains() and Add() methods.

使用XStream读取XML(Read XML using XStream)

最满意答案

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