Win32 CreateWindow（）调用在子线程中挂起？(Win32 CreateWindow() call hangs in child thread?)

 @DamirDžilić - 没有任何真实的代码可以发表评论，我们只能给出概念建议。 你将不得不将每一手牌与所有可能的扑克手牌进行比较，从最高等级的手牌到一对牌手。 
 
 我个人建议每张卡都是一个对象： 
 
var card = {suit: "S", value: 9};
 
 然后，一只手将是一组卡片对象。 
 
 然后，您可以分别查看套装和卡片价值。 如果卡值在2到14之间并且您转换为J，Q，K，A仅用于显示，则会更容易。 
 
 然后，每个可能的扑克手（一对，三种，四种，同花顺，直线等等）将按照他们在扑克中的价值得分（对= 1，两对= 2，三对）一种= 3，直= 4，冲洗= 5，满屋= 6，同花顺= 7，四种= 8，同花= 9）。 
 
 然后，我建议你给每种类型的手一个得分，其中包括10000 *手牌值+ 100 *顶级卡牌+踢球者值。 因此，一对带有K踢球的8对值得： 
 
(2*10000) + (8*100) + 13 = 20,813
 
 并且，带有A踢球者的三个2将是： 
 
(3*10000) + (2*100) + 14 = 30,214
 
 使用这种类型的得分系统，手牌值总是占主导地位，然后是手牌得分的顶级牌（例如3个女王击败3个等），然后踢球者打破任何关系。 
 
 你可以自己编写代码来确定你拥有什么样的牌，但基本上你必须检查直道，冲洗以及你拥有多少普通牌。 我可能会首先寻找配对，只有在没有配对的情况下才能寻找直道或冲洗，并且我会找到一个能够寻找每个配对的功能。 

@DamirDžilić - without any real code to comment on, we can only give conceptual advice. You're going to have to just compare each hand against all possible poker hands, starting with the highest rated hand down to a single pair.
 
I'd personally suggest that each card be an object:
 
var card = {suit: "S", value: 9};
 
Then, a hand would be an array of card objects.
 
You can then look at suit and card value separately. It would be easier if card values where 2 through 14 and you convert to J, Q, K, A only for display.
 
Then, each possible poker hand (pair, three of a kind, four of a kind, flush, straight, etc...) would get a score in order of their value in poker (pair = 1, two pair = 2, three of a kind = 3, straight = 4, flush = 5, full house = 6, straight flush = 7, four of a kind = 8, straight flush = 9).
 
Then, I'd suggest you give each type of hand a score which consist of 10000*hand value + 100*top card in hand + value of kicker. So, a pair of 8's with a K kicker would be worth:
 
(2*10000) + (8*100) + 13 = 20,813
 
And, three 2's with an A kicker would be:
 
(3*10000) + (2*100) + 14 = 30,214
 
With this type of scoring system, the hand value always dominates, then the top card that's part of the scoring piece of the hand (e.g. 3 queens beats 3 eights), then the kicker breaks any ties.
 
It would be up to you to write the code for figuring out what kind of hand you have, but basically you have to examine for straights, flushes and how many common cards you have. I'd probably look for pairs first and only if there are no pairs do you look for straights or flushes and I'd make a function to look for each.