从while循环获取一些记录到数组，然后通过电子邮件发送这些记录(Get some records from a while loop to an array, then send these records in an email)

 我有一个while循环： 
 
$users = mysqli_query($con, "SELECT * FROM table");
while($row = mysqli_fetch_array($users)) {          
  if    ($row['column1'] !=  $row['column2']) {
    echo "There is a different between column1 and column2<br />";
  }
}
 
 我想得到column1与column2不同的所有记录，并将这些值放入电子邮件中。 
 
 电子邮件看起来像这样： 
 
ID     Column1   Column2
1      111       222
4      222       333
 
 我以为我可以用array_push做到这一点，但我没有让它工作。 
 
 知道如何完成这项工作吗？ 

I have a while loop:
 
$users = mysqli_query($con, "SELECT * FROM table");
while($row = mysqli_fetch_array($users)) {          
  if    ($row['column1'] !=  $row['column2']) {
    echo "There is a different between column1 and column2<br />";
  }
}
 
I want to get all the records where column1 is different from column2 and get these values into an email.
 
The email looks like this:
 
ID     Column1   Column2
1      111       222
4      222       333
 
I thought I could do this with array_push but I'm not getting it to work.
 
Any idea how to get this done?

原文：https://stackoverflow.com/questions/29167423