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 用这5个字符串制作数组。 拿一个标签不要忘记连接它（IBOutlet不是IBAction）。 然后在接口构建器（IBAction方法而不是IBOutlet）中使用2个按钮一个用于递增，一个用于递减连接它们。 现在你有2个方法用于下一个按钮和上一个按钮。 在下一个按钮方法中，将数组的objectAtIndex增加1并在之前的按钮方法中将ObjectAtindex减少1.在标签上显示当前索引 
 
 注意：如果条件不超过[数组计数]，则将条件设置为递增，并且在递减时不应超过0 
 
 你可以像这样制作自定义按钮 
 
    UIButton *Button = [UIButton buttonWithType:UIButtonTypeCustom];  
 
 在按钮上执行这样的方法 
 
     [Button addTarget:self action:@selector(YourMethod) forControlEvents:UIControlEventTouchUpInside];
 
 然后将此按钮添加到您的视图[YourViewName addSubview：Button]; 是的，您需要设置框架，以便将此按钮放在视图中 

make array with that 5 strings . take one label do not forget to connect it(IBOutlet not IBAction). then take 2 buttons one for increment and one for decrement connect them too in interface builder(IBAction method not IBOutlet). now you have 2 methods for next button and previous button. in next button method increment objectAtIndex of array by 1 and in previous button method decrease ObjectAtindex by 1. show the current index on label 
 
Note: put if condition in increment like if its not exceeding [array count] and in decrement it should not exceed 0
 
you can make custom button like this
 
    UIButton *Button = [UIButton buttonWithType:UIButtonTypeCustom];  
 
perform method like this on button
 
     [Button addTarget:self action:@selector(YourMethod) forControlEvents:UIControlEventTouchUpInside];
 
then add this button to your view [YourViewName addSubview:Button]; yes you need to set frame where you want to put this button in view