首页 \ 问答 \ UITableView contentInset使表视图水平滚动除了垂直(UITableView contentInset makes table view scroll horizontally in addition to vertically)

UITableView contentInset使表视图水平滚动除了垂直(UITableView contentInset makes table view scroll horizontally in addition to vertically)

我在代码中创建了一个UITableViewController,并将它推到导航堆栈的顶部。 它的表格视图旨在显示文本项目的简单列表。

我需要添加一些contentInset到我的表格视图,我在我的UITableViewController的init方法中添加

self.tableView.contentInset = UIEdgeInsetsMake(7.0f, 5.0f, 7.0f, 5.0f);

然而,当我加载表视图时,似乎左和右的contentInset实际上已将我的表视图的宽度拉伸了10倍。我现在看到一个小的水平可滚动区域。 我不想在我的桌子视图上进行任何水平滚动。 如果我删除了contentInset代码,我的表格视图的行为很简单,即仅提供垂直滚动。 我如何保持这种状态,但使用我的contentInset? 我试图在viewWillAppear中将contentSize.width减少10,但它没有效果。

这似乎是重复的,但没有可接受的答案: UITableView ContentInsets水平滚动内容

在模拟中,我用虚线标记了所需的contentInset ---

在这里输入图像描述

谢谢。


I'm creating a UITableViewController in code and pushing it on top of the navigation stack. It's table view is intended to just show a simple list of text items.

I need to add some contentInset to my table view which I add in the init method of my UITableViewController

self.tableView.contentInset = UIEdgeInsetsMake(7.0f, 5.0f, 7.0f, 5.0f);

However, when I load the table view it seems the left and right contentInset have actually stretched the width of my table view by 10. I'm now seeing a small horizontal scrollable area. I don't want any sort of horizontal scrolling on my table view. If I remove the contentInset code, my table view behaves plainly i.e. simply provides for vertical scrolling. How I can keep just like that but with my contentInset in place? I tried reducing my contentSize.width by 10 in viewWillAppear, it had no effect.

This seems to be a duplicate but with no acceptable answer: UITableView ContentInsets scrolling content horizontally

In the mock I have marked the desired contentInset with dashed line ---

enter image description here

Thanks.


原文:https://stackoverflow.com/questions/16260612
更新时间:2024-03-30 18:03

最满意答案

试试这个:

使用Javascript:

$("#browse").change(function () {
    var files = this.files;
    var reader = new FileReader();
    var name = this.value;
    reader.onload = function (e) {
        $("#preview").append("<a>'" + name + "'</a><img src='" + e.target.result + "' width='30' height='30' />");
        alert(e.target.result);
    };
    reader.readAsDataURL(files[0]);
});

HTML:

<input type="file" id="browse" />
<div id="preview"></div>

我想,你可以按照你想要的方式将e.target.result发送到服务器。

工作演示http//jsfiddle.net/ashishanexpert/3QyEB/


Try this:

Javascript:

$("#browse").change(function () {
    var files = this.files;
    var reader = new FileReader();
    var name = this.value;
    reader.onload = function (e) {
        $("#preview").append("<a>'" + name + "'</a><img src='" + e.target.result + "' width='30' height='30' />");
        alert(e.target.result);
    };
    reader.readAsDataURL(files[0]);
});

HTML:

<input type="file" id="browse" />
<div id="preview"></div>

I think, you can send e.target.result to server in the way you want to.

Working Demo: http://jsfiddle.net/ashishanexpert/3QyEB/

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