首页 \ 问答 \ 具有UISwitch功能的iPhone UIButton(iPhone UIButton with UISwitch functionality)

具有UISwitch功能的iPhone UIButton(iPhone UIButton with UISwitch functionality)

有没有办法用开关状态的自定义图形来实现UISwitch? 或者作为另一种替代方法,UIButton具有UISwitch功能?


Is there either a way to implement UISwitch with custom graphics for the switch-states? Or as an alternative the other way round, an UIButton with UISwitch functionality?


原文:https://stackoverflow.com/questions/2255166
更新时间:2022-06-23 14:06

最满意答案

这将与您发布的单个示例相匹配:

<html>
  <body>
    <script type="text/javascript">
      text = '#container a.filter(.top).filter(.bottom).filter(.middle)';
      matches = text.match(/^[^.]*|\.[^.)]*(?=\))/g);
      document.write(matches);
    </script>
  </body>
</html>

这产生:

#container a,.top,.bottom,.middle 

编辑

这里有一个简短的解释:

^         # match the beginning of the input
[^.]*     # match any character other than '.' and repeat it zero or more times
          #
|         # OR
          #
\.        # match the character '.'
[^.)]*    # match any character other than '.' and ')' and repeat it zero or more times
(?=       # start positive look ahead
  \)      #   match the character ')'
)         # end positive look ahead

编辑第二部分

正则表达式寻找两种类型的字符序列:

  1. 一个或多个字符从字符串的开头到第一个字符开始. ,正则表达式: ^[^.]*
  2. 或者它匹配以a开头的字符序列. 之后是0以外的字符.)\.[^.)]* ,但必须在它之前: (?=\)) 。 这最后一项要求导致.filter 匹配。

This will match the single example you posted:

<html>
  <body>
    <script type="text/javascript">
      text = '#container a.filter(.top).filter(.bottom).filter(.middle)';
      matches = text.match(/^[^.]*|\.[^.)]*(?=\))/g);
      document.write(matches);
    </script>
  </body>
</html>

which produces:

#container a,.top,.bottom,.middle 

EDIT

Here's a short explanation:

^         # match the beginning of the input
[^.]*     # match any character other than '.' and repeat it zero or more times
          #
|         # OR
          #
\.        # match the character '.'
[^.)]*    # match any character other than '.' and ')' and repeat it zero or more times
(?=       # start positive look ahead
  \)      #   match the character ')'
)         # end positive look ahead

EDIT part II

The regex looks for two types of character sequences:

  1. one ore more characters starting from the start of the string up to the first ., the regex: ^[^.]*
  2. or it matches a character sequence starting with a . followed by zero or more characters other than . and ), \.[^.)]*, but must have a ) ahead of it: (?=\)). This last requirement causes .filter not to match.

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