停止不被中断的线程(stop thread that does not get interrupted)

//For toggle the LED for certain length of time use the delay() 
//call delay(UNIT) to pause execution of UNIT milliseconds
//long unit *3 , short = unit
void displayMorseCode(byte* msg, int len) {
int delayT = 0;
int unit = 300;
  // TODO :Interpret the message toggle LED on and off to display the 
           morse code
for (int i = 0 ; i< len; i++)
{
if (msg[i] == 1) {
    digitalWrite(LED_PIN,HIGH); 
    delayT = 3*unit;
}
else {
    digitalWrite(LED_PIN,LOW); 
    delayT = unit;
}

delay(delayT);

} 
 
 这是一个非常简单的答案，它将根据收到的字节更改持续时间。 现在你必须为每个字节创建一个字典，这样根据字节（即S = short，short，short）你创建写输出，就像我给你看的那样，但是你应该用new更改digitalWrite（）功能，将创建每个字母的摩尔斯电码。 所以if条件是每个字母（即if (msg[i] == 83) - 十进制ASCII中的S-） 

//For toggle the LED for certain length of time use the delay() 
//call delay(UNIT) to pause execution of UNIT milliseconds
//long unit *3 , short = unit
void displayMorseCode(byte* msg, int len) {
int delayT = 0;
int unit = 300;
  // TODO :Interpret the message toggle LED on and off to display the 
           morse code
for (int i = 0 ; i< len; i++)
{
if (msg[i] == 1) {
    digitalWrite(LED_PIN,HIGH); 
    delayT = 3*unit;
}
else {
    digitalWrite(LED_PIN,LOW); 
    delayT = unit;
}

delay(delayT);

} 
 
This is a very simple answer, that will change the duration depending on the byte received. Now you must create a dictionary for each byte, so that depending on the byte (i.e. S = short,short,short) you create the write output, in the same way I showed you, but you should change digitalWrite() with the new function, that will create each letter's morse code. So the if condition would be for each letter (i.e. if (msg[i] == 83) - the S in decimal ASCII-)