适用于多个开发人员的iOS Xcode项目文件共享(iOS Xcode project file sharing for multiple developers)
在同一个iOS项目中工作的多个开发人员的最佳实践是什么? 当多个开发人员正在处理同一个Xcode项目时,有没有办法避免重置代码签名构建设置(同时保持其余的共享)?
What is the best practice for multiple developers working on the same iOS project? Is there a way to avoid having to reset the code signing build settings (while keeping the rest shared) when multiple developers are working on the same Xcode project?
原文:https://stackoverflow.com/questions/7283790
更新时间:2022-02-24 17:02
最满意答案
在某些RDMS中,您不必指定FROM子句,因为它已包含在语句中。 尝试这个:
UPDATE contacts c INNER JOIN table2 t ON c.contactId = t.conatctId SET c.companyId = t.newComapnyId
In some RDMS you don't have to specify the FROM-clause as it's already included in the statement. Try this:
UPDATE contacts c INNER JOIN table2 t ON c.contactId = t.conatctId SET c.companyId = t.newComapnyId
相关问答
更多-
JOIN中的SQL语法错误(sql syntax error in JOIN)[2023-10-05]
你不能有两个这样的FROM子句...... 你可能意味着加入,但你需要另一个ON条件: SELECT * FROM ##temporderstable P JOIN supporder Y ON P.catalogid = Y.backorder JOIN backorder B ON B.xxxxxxxxx = P.xxxxyyyyy GROUP BY P.catalogid; 第二个ON需要引用一列B和一列P或Y. You can't have two FROM clauses li ... -
link to应该是link_to 。 link to should be link_to.
-
使用2个内部联接更新(Update using 2 inner joins)[2023-01-26]
你可以使用以下 UPDATE table1 t1 SET t1.VALUE = (SELECT t3.VALUE FROM table2 t2, table3 t3 WHERE t1.name = t2.name AND t2.address = t3.address) you can use the following UPDATE table1 t1 SET t1.VALUE = (SELECT t3.VALUE FROM t ... -
错误1064是MySQL语法错误。 正确的MySQL语法是: UPDATE newsreactions nr INNER JOIN users u ON nr.memberId = u.id SET nr.enabled = 0 WHERE u.active = 0 AND u.comment LIKE '%spam%'; 笔记: JOIN进入UPDATE子句。 表别名使查询更易于编写和读取。 我猜测enabled和active确实是数值。 如果是这样,请不要使用单引 ...
-
快速搜索“informix sql update”将返回两个描述UPDATE命令语法的参考手册页。 两者都没有表明支持非标准的FROM子句。 标准SQL使用相关子查询来实现此目的。 您的查询应该类似于 update TableA set MOdule_id = (select TableB.MOdule_id from TableB on TableA.end_Slot_id = Slot_Id) where Slot_Id = 'AAA' and exists ( s ...
-
您不应该在更新中使用from,因为更新表已在UPDATE子句中定义 UPDATE users as u JOIN updated_phone as a on a.phone like 'u.phone_no%' SET u.phone_no= a.phone where u.phone_no like '88%' you don't should use from in update because the updating table is already define in UPDA ...
-
在某些RDMS中,您不必指定FROM子句,因为它已包含在语句中。 尝试这个: UPDATE contacts c INNER JOIN table2 t ON c.contactId = t.conatctId SET c.companyId = t.newComapnyId In some RDMS you don't have to specify the FROM-clause as it's already included in the statement. Try this: UPDATE c ...
-
这是有效的语法: UPDATE tblMitarbeiterUUID x JOIN arbeiter y ON x.idMitarbeiterUUID = y.fidMitarbeiterUUID SET x.dtPassword="A" WHERE y.id=1 This is valid syntax: UPDATE tblMitarbeiterUUID x JOIN arbeiter y ON x.idMitarbeiterUUID = y.fidMitarbeiterUUID S ...
-
MySQL中的正确语法是: UPDATE TableA INNER JOIN TableB ON TableA.id = TableB.id SET TableA.field1 = TableB.field1 WHERE TableA.field1 <> ''; 注意:您不能将LIMIT与JOIN一起使用。 如果您想使用LIMIT ,您可以: UPDATE TableA SET TableA.field1 = (SELECT TableB.field1 FRO ...
-
INNER JOIN BlogEntryItems ON Table2.ID = BlogEntryItem 。 忘记表名中的内容 INNER JOIN BlogEntryItems ON Table2.ID=BlogEntryItem. Forget something in table name