虽然循环不起作用(While loop doesn't work)
$r = mysql_query ( "SELECT guid FROM characters" ); if (mysql_num_rows($r) != 0) { while ( $row == mysql_fetch_array ( $r ) ) { $cap = rand ( 0, $char ); if ($row ['guid'] != $cap) { $captain = rand ( 0, $char ); } } } else { $captain = rand ( 0, $char ); }
这段代码应该返回我的字符guid,它还没有记录在字符表中。 第一部分如果有效,但循环根本不起作用,我试图添加打印“文本”; 在它,但它没有返回什么。
$r = mysql_query ( "SELECT guid FROM characters" ); if (mysql_num_rows($r) != 0) { while ( $row == mysql_fetch_array ( $r ) ) { $cap = rand ( 0, $char ); if ($row ['guid'] != $cap) { $captain = rand ( 0, $char ); } } } else { $captain = rand ( 0, $char ); }
This code should return me the guid of character, which is not recorded in the characters table yet. The first part with if works, but the loop doesn't work at all, I tried to add print "text"; in it but it didn't return nothing.
原文:https://stackoverflow.com/questions/3326541
更新时间:2023-12-06 20:12
最满意答案
你的帆布尺寸是400 x 400吗? 是否有一个容器拿着带有灰色背景的画布(#808080)?
如果是这样,这是一个CSS问题。 尝试给画布一种漂浮的风格:左。 或者将画布绝对定位在它的容器中。
<canvas width="400" height="400" style="float:left"></canvas>
要么
<div style="position:relative"><!-- containing element --> <canvas width="400" height="400" style="top:0; left:0;position:absolute"> </canvas> </div>
Is the size of your canvas 400 x 400? And is there a container that is holding the canvas with a background with that gray color (#808080)?
If so, this is a CSS problem. Try giving the canvas a style of float:left. Or absolutely positioning the canvas within it's container.
<canvas width="400" height="400" style="float:left"></canvas>
or
<div style="position:relative"><!-- containing element --> <canvas width="400" height="400" style="top:0; left:0;position:absolute"> </canvas> </div>
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帆布有一个偏移量(canvas has an offset)[2023-07-11]
你的帆布尺寸是400 x 400吗? 是否有一个容器拿着带有灰色背景的画布(#808080)? 如果是这样,这是一个CSS问题。 尝试给画布一种漂浮的风格:左。 或者将画布绝对定位在它的容器中。 要么相关文章
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