首页 \ 问答 \ 在Spring中将包含实体ID的@RequestBody属性转换为相应的实体(Convert @RequestBody attribute containing entity ID to corresponding entity in Spring)

在Spring中将包含实体ID的@RequestBody属性转换为相应的实体(Convert @RequestBody attribute containing entity ID to corresponding entity in Spring)

请问,是否可以实现包含实体ID的请求主体属性自动转换为相应的JPA实体?

@Entity
public class Foo {
    @Id
    private Long id;

    // getters and setters
}  

public class Bar {
    private Foo foo;

    // getters and setters
}

@Controller
public class Controller {

    @RequestMapping(path="/foo", method=RequestMethod.POST)
    public void convertFooAction(@RequestBody Bar bar) {
        // variable bar with foo attribute containing entity with corresponding ID
    }
}

POST请求中使用的示例JSON请求主体:

{ "foo": 1 }

无论@RequestBody类是否是@Entity ,它都应该在任何情况下都能正常工作。

感谢您的任何建议。


Please, is it possible to achieve automatic conversion of request body attribute containing entity ID to corresponding JPA entity?

@Entity
public class Foo {
    @Id
    private Long id;

    // getters and setters
}  

public class Bar {
    private Foo foo;

    // getters and setters
}

@Controller
public class Controller {

    @RequestMapping(path="/foo", method=RequestMethod.POST)
    public void convertFooAction(@RequestBody Bar bar) {
        // variable bar with foo attribute containing entity with corresponding ID
    }
}

Example JSON request body used in POST request:

{ "foo": 1 }

It should work in every case, whether the @RequestBody class is @Entity or not.

Thanks for any advice.


原文:https://stackoverflow.com/questions/45464777
更新时间:2023-09-04 19:09

最满意答案

要做到这一点,你必须使用:checked选择器。 虽然JP的回答很好,但我可能会这样做:

$('#form1').submit(function() {
    if ($('input:checkbox', this).is(':checked') &&
        $('input:radio', this).is(':checked')) {
        // everything's fine...
    } else {
        alert('Please select something!');
        return false;
    }
});

一对笔记:

  • 我认为它更好地使用is函数,它返回选择器的布尔值。
  • 您可以使用:radio:checkbox作为选择表单中所有收音机和复选框的快捷方式。 然而, 根据jQuery手册 ,使用这些选择器是不好的做法,而无需在它们之前指定input ,因为它们评估为*:checkbox*:radio否则为非常慢的选择器。
  • 通过传递this作为第二个参数,我们为搜索指定一个上下文 ,并且因此仅搜索当前表单中的复选框和无线电输入。 没有它,如果页面中出现另一种形式,我们可能会得到误报。

To do this you have to use the :checked selector. Although JP's answer is fine, I'd probably do this:

$('#form1').submit(function() {
    if ($('input:checkbox', this).is(':checked') &&
        $('input:radio', this).is(':checked')) {
        // everything's fine...
    } else {
        alert('Please select something!');
        return false;
    }
});

Couple of notes:

  • I think it reads better to use the is function, which returns a boolean of the selector.
  • You can use :radio and :checkbox as a shortcut for selecting all radios and checkboxes in a form. However, according to the jQuery manual, it is bad practice to use these selectors without specifying input before them, as they evaluate to *:checkbox and *:radio otherwise, which are very slow selectors.
  • By passing this as the second argument we are specifying a context for the search, and thus are only searching for checkboxes and radio inputs inside the current form. Without it we might get false positives if there happens to be another form in the page.

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