首页 \ 问答 \ Solr:当匹配= 1且NGroups = 1时,没有返回任何组(Solr: No Groups returned when Matches = 1 and NGroups = 1)

Solr:当匹配= 1且NGroups = 1时,没有返回任何组(Solr: No Groups returned when Matches = 1 and NGroups = 1)

我正在查询solr并将结果分组。 一切正常,直到我做出一个特定的查询,返回(据说)只有1个结果。 调试显示存在匹配和ngroup,但没有从solr返回任何组。 任何指向解决方案的指针都将受到赞赏。

Solr分组错误说明


I am querying solr and results are grouped. Everything is working fine until I make a specific query which returns (supposedly) only 1 result. Debugging shows that there was a match and a ngroup, but no groups are returned from solr. Any pointers to the solution would be appreciated.

Solr Grouping Error Description


原文:https://stackoverflow.com/questions/40784360
更新时间:2022-05-06 22:05

最满意答案

FUN=my.mse正在劫持你的lapply apply尝试。 我想你想要:

lapply(B.list, function(x) apply(x, 2, my.mse))

您不能为lapply指定FUN并在同一个调用中应用(除非您使用Konrad建议的位置匹配)。 发生了什么事情,你的电话匹配是这样的:

lapply(B.list, FUN=my.mse, ...=list(apply, MARGIN=2))

然后在第一次迭代中导致尝试评估:

my.mse(B.list[[1]], apply, MARGIN=2)

而不是你期望的apply(B.list[[1]], 2, my.mse) 。 由于my.mse只接受一个参数,因此您会收到有关“unused arguments”的错误。 仔细观察,“未使用的参数”是apply函数的主体。


FUN=my.mse is hijacking your attempt to lapply apply. I think you want:

lapply(B.list, function(x) apply(x, 2, my.mse))

You can't specify FUN for both lapply and apply in the same call (unless you use positional matching as Konrad suggests). What's happening is that your call is getting matched like so:

lapply(B.list, FUN=my.mse, ...=list(apply, MARGIN=2))

Which then in your first iteration leads to the attempt to evaluate:

my.mse(B.list[[1]], apply, MARGIN=2)

instead of your expected apply(B.list[[1]], 2, my.mse). Since my.mse only accepts one argument, you get the error about "unused argument". If you look closely, the "unused argument" is the body of the apply function.

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