首页 \ 问答 \ 最近看“设计模式”,有人说:容易克隆的类才方便用 Prototype-原型模式,请问怎样才叫容易克隆?

最近看“设计模式”,有人说:容易克隆的类才方便用 Prototype-原型模式,请问怎样才叫容易克隆?

更新时间:2023-04-18 16:04

最满意答案

Imports System.Text.RegularExpressions
Public Class Form1
    Private Sub Form1_Load(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles MyBase.Load
        Dim a As String = "ABCDEFGHIJKLMNOPQRSTUVWXYZ"
        Dim g() As Char = a.ToCharArray
        Dim MyRandom As New Random
        Dim bs As String = ""
        For i = 1 To 20
            bs &= g(MyRandom.Next(0, g.GetUpperBound(0) + 1))
        Next
        Dim gs() As String = (From mt As Match In Regex.Matches(bs, "[A-Z]") Select mt.Value).ToArray
        System.Array.Sort(gs)
        gs = (From mt As Match In Regex.Matches(Join(gs, ""), "([A-Z])\1*") Select mt.Value).ToArray
        Dim g_len() As Integer
        g_len = (From mt As Match In Regex.Matches(Join(gs, ""), "([A-Z])\1*") Select mt.Length).ToArray ' 使用数组元素作为计数器g_len
        System.Array.Sort(g_len, gs)
        Label1.Text = "出现次数最多的字母:" & gs(gs.GetUpperBound(0)).Substring(0, 1) & " 共出现" & g_len(g_len.GetUpperBound(0)) & "次" & vbCrLf & "没有出现的字母是:" & Join(a.Split(bs.ToCharArray), "")
    End Sub
End Class

其他回答

static dictionary<char, int> test4()

{

dictionary<char, int> dicresult = new dictionary<char, int>();

random random = new random();

for (int i = 0; i < 20; i++)

{

char temprandom = (char)random.next(65, 91);

if (dicresult.containskey(temprandom))

{

dicresult[temprandom]++;

}

else

{

dicresult.add(temprandom, 1);

}

}

return dicresult;

}

 

最后返回的dic里面保存的是key(出现的大写字母),value(出现的大写字母的次数),剩下你需要做的工作就是遍历这个dic,找出value最大的那些key和value即可。

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