如何删除vim Powerline中的段？(How to remove a segment in vim Powerline?)

 我正在使用vim Powerline ，默认情况下它在电力线上有很多段。 超过我想要的。 
 
 我想删除几个默认的。 具体来说，那个告诉我我的git分支，文件编码，源语言，行/列号，说unix（可能行结束）的那个。 
 
 在文档中 ，他们说你应该能够使用Pl＃Theme＃RemoveSegment。 
 
 所以我在我的〜/ .vimrc中添加了call Pl#Theme#RemoveSegment('fugitive') ，然后运行:PowerlineClearCache并重新加载文件，但git分支仍在那里。 也许我的名字错了，我猜这是根据这里的命名进入我的git分支的那个。 
 
 如果有一种方法可以反映一些变量，看看哪些段被注册，这将是有用的，但我不知道我是否得到了错误的名称，或者错误地调用了方法，或者是什么。 

I'm using vim Powerline, it comes by default with quite a few segments in the powerline. More than I want.
 
I'd like to remove several of the default ones. Specifically, the one that tells me my git branch, the file encoding, the source language, the line/col number, the one that says unix (probably line ends).
 
In the docs, they say you should be able to use Pl#Theme#RemoveSegment.
 
So I added call Pl#Theme#RemoveSegment('fugitive') to my ~/.vimrc, and then ran :PowerlineClearCache and reloaded the file, but the git branch is still there. Perhaps I'm getting the name wrong, I guessed that this is the one that enters my git branch based on the naming from here.
 
If there's a way to reflect on some variable and see what segments are registered, that would be useful, but I can't tell if I'm getting the name wrong, or invoking the method incorrectly, or what.

原文：https://stackoverflow.com/questions/11404863