首页 \ 问答 \ 如何将SQL查询的输出插入临时表中?(How to insert the output of a SQL Query into a temporary table?)

如何将SQL查询的输出插入临时表中?(How to insert the output of a SQL Query into a temporary table?)

我正在使用SQL Server 2012,并且想要使用T-SQL执行以下操作:

  1. 创建一个临时表(我们称它为#temptable )。

  2. 使用SELECT语句将位于现有数据库中的表的值插入到#temptable

  3. 编写一个将查询#temptableSELECT语句。

我已经尝试了以下,但它似乎语法不正确,或许我试图做的是不允许的。

USE MyDatabase

CREATE TABLE #temptable
GO

INSERT INTO #TempTable
SELECT  [Col A], [Col B], [Col C]

FROM MYLIST

WHERE [MONTH OF STAY] = '2018-03-01'

AND [Property] = 'ABC'

SELECT * FROM #temptable

我如何向前迈进?


I am using SQL Server 2012 and I want to perform the following operations using T-SQL:

  1. Create a temporary table (let's call it #temptable).

  2. Insert values from tables located in an existing database into #temptable using a SELECT statement.

  3. Write a SELECT statement that will query the #temptable.

I have tried the following but it seems the syntax is not correct or perhaps what I am trying to do is not allowed.

USE MyDatabase

CREATE TABLE #temptable
GO

INSERT INTO #TempTable
SELECT  [Col A], [Col B], [Col C]

FROM MYLIST

WHERE [MONTH OF STAY] = '2018-03-01'

AND [Property] = 'ABC'

SELECT * FROM #temptable

How do I move forward with this?


原文:https://stackoverflow.com/questions/48474513
更新时间:2023-03-19 17:03

最满意答案

使用以前的公式,我将使用以下内容:

 =SUMPRODUCT((LEFT(TEXT(C$8,"mmm"),3)=LEFT($O$3:$O$12,3))*(DAY(C$8)=--RIGHT($O$3:$O$12,2)))

基本上,如果月份的前三个字母匹配且日期的天数匹配,则公式将返回值1,对于Excel数学,该值等于true。 所有其他结果应该返回0.还必须在列表中没有重复的假日日期,否则公式将返回大于1的值。但是也有方法,但这是一个后续问题。


Working off your previous formula I would use something along the lines of the following:

 =SUMPRODUCT((LEFT(TEXT(C$8,"mmm"),3)=LEFT($O$3:$O$12,3))*(DAY(C$8)=--RIGHT($O$3:$O$12,2)))

Basically the formula will return the value of 1 which is equivalent to true for excel math if the first three letters of the month match and the date's day number match. All other results should return 0. It is also imperative that you do not have duplicate holiday dates in your list or the formula will return a value greater than 1. But there are ways around that too, but that is a follow up question.

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