首页 \ 问答 \ 在Rascal中使用“父”标签注释ADT /节点树(Annotating a ADT/Node tree with “parent” labels in Rascal)

在Rascal中使用“父”标签注释ADT /节点树(Annotating a ADT/Node tree with “parent” labels in Rascal)

我想创建一个树(使用NodeADT ),其中每个节点都有一个指向其父节点的注释。 下面是一个简单链表数据结构的示例:

import util::Math;
import IO;
import Node;

anno LinkedList LinkedList@parent;
anno int LinkedList@something;

data LinkedList = item(int val, LinkedList next)
                | last(int val)
                ;

public LinkedList linkedList =  item(5,
                                    item(4,
                                        item(3,
                                            item(2,
                                                last(1)[@something=99]
                                            )[@something=99]
                                        )[@something=99]
                                    )[@something=99]
                                )[@something=99];

public LinkedList addParentAnnotations(LinkedList n) {
    return top-down visit (n) {
        case LinkedList x: {
            /* go through all children whose type is LinkedList */
            for (LinkedList cx <- getChildren(x), LinkedList ll := cx) {
                /* setting the annotation like this doesn't seem to work */
                cx@parent = x;
                // DOESN'T WORK EITHER: setAnnotation(cx, getAnnotations(cx) + ("parent": x));
            }
        }
    }
}

执行addParentAnnotations(linkedList)产生以下结果:

rascal>addParentAnnotations(linkedList);
LinkedList: item(
  5,
  item(
    4,
    item(
      3,
      item(
        2,
        last(1)[
          @something=99
        ])[
        @something=99
      ])[
      @something=99
    ])[
    @something=99
  ])[
  @something=99
]

I want to create a tree (using a Node or ADT) in which every node has an annotation pointing back to its parent. Below is an example with a simple linked list data structure:

import util::Math;
import IO;
import Node;

anno LinkedList LinkedList@parent;
anno int LinkedList@something;

data LinkedList = item(int val, LinkedList next)
                | last(int val)
                ;

public LinkedList linkedList =  item(5,
                                    item(4,
                                        item(3,
                                            item(2,
                                                last(1)[@something=99]
                                            )[@something=99]
                                        )[@something=99]
                                    )[@something=99]
                                )[@something=99];

public LinkedList addParentAnnotations(LinkedList n) {
    return top-down visit (n) {
        case LinkedList x: {
            /* go through all children whose type is LinkedList */
            for (LinkedList cx <- getChildren(x), LinkedList ll := cx) {
                /* setting the annotation like this doesn't seem to work */
                cx@parent = x;
                // DOESN'T WORK EITHER: setAnnotation(cx, getAnnotations(cx) + ("parent": x));
            }
        }
    }
}

Executing addParentAnnotations(linkedList) yields the following result:

rascal>addParentAnnotations(linkedList);
LinkedList: item(
  5,
  item(
    4,
    item(
      3,
      item(
        2,
        last(1)[
          @something=99
        ])[
        @something=99
      ])[
      @something=99
    ])[
    @something=99
  ])[
  @something=99
]

原文:https://stackoverflow.com/questions/19028623
更新时间:2023-05-01 13:05

最满意答案

\w包括数字; 它相当于[A-Za-z0-9_] 。 所以无论哪种方式,你都允许他们。


\w includes digits; it's equivalent to [A-Za-z0-9_]. So either way you're allowing them.

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