Python中非常简单的并发编程(Very simple concurrent programming in Python)

 我有一个简单的Python脚本，它使用了两个更复杂的Python脚本，并对结果进行了一些处理。 
 
 我有两个模块，Foo和Bar，我的代码如下所示： 
 
import Foo
import Bar

output = []

a = Foo.get_something()
b = Bar.get_something_else()

output.append(a)
output.append(b)
 
 两种方法都需要很长时间才能运行，并且两者都不依赖于其他方法，所以显而易见的解决方案是并行运行它们。 我该如何做到这一点，但要确保顺序得以保持： 无论哪个人首先完成，必须等待另一个完成才能继续执行脚本 。 
 
 如果我没有把自己弄清楚，请告诉我，我试图让示例代码尽可能简单。 
 
 编辑： 
 
 感谢Amber，您的解决方案只需稍作修改即可使用。 
 
 当创建每个线程时，不要调用start（），而是像下面这样设置它们： 
 
threadname = threading.Thread(target=foo)
threadname.start()
 
 没有这个，我得到了错误AttributeError: 'NoneType' object has no attribute 'join'和一些非常奇怪的并发行为。 如果你在下面编辑你的答案，我会将其标记为已解决。 

I have a simple Python script that uses two much more complicated Python scripts, and does something with the results.
 
I have two modules, Foo and Bar, and my code is like the following:
 
import Foo
import Bar

output = []

a = Foo.get_something()
b = Bar.get_something_else()

output.append(a)
output.append(b)
 
Both methods take a long time to run, and neither depends on the other, so the obvious solution is to run them in parallel. How can I achieve this, but make sure that the order is maintained: Whichever one finishes first must wait for the other one to finish before the script can continue.
 
Let me know if I haven't made myself clear enough, I've tried to make the example code as simple as possible.
 
EDIT:
 
Thanks Amber, your solution works with one slight change.
 
Instead of calling start() on each thread when it is created, I set them up like so:
 
threadname = threading.Thread(target=foo)
threadname.start()
 
Without this I was getting the error AttributeError: 'NoneType' object has no attribute 'join' and some very weird behaviour with the concurrency. If you edit your answer below I will mark it as solved.

原文：https://stackoverflow.com/questions/10475448