Python Cookbook适用于Python 2.4(Python Cookbook is for Python 2.4)
Python Cookbook 2nd edition已针对Python 2.4进行了更新。 使用Python版本2.5或2.6学习本书还可以吗?
Python Cookbook 2nd edition is updated for Python 2.4. Is it still ok to study the book using Python version 2.5 or 2.6?
原文:https://stackoverflow.com/questions/4253903
更新时间:2022-02-15 18:02
最满意答案
% Extract table data and linearly index it tdata = T{:,:}; [~,row] = ismember({S.rownamefield}, T.Properties.RowNames); col = [S.columnnumberfield]; pos = sub2ind(size(tdata),rowpos, col); val = tdata(pos); % Assign to struct for ii = 1:numel(S) S(ii).field3 = val(ii); end
您可以使用Suever的解决方案和
deal()
来一次性分配值(必须先使用num2cell(val)
),而不是for循环。 无论更快,更直观。% Extract table data and linearly index it tdata = T{:,:}; [~,row] = ismember({S.rownamefield}, T.Properties.RowNames); col = [S.columnnumberfield]; pos = sub2ind(size(tdata),rowpos, col); val = tdata(pos); % Assign to struct for ii = 1:numel(S) S(ii).field3 = val(ii); end
Instead of the for-loop, you can use Suever's solution with the
deal()
to assign values in one go (have tonum2cell(val)
first). Whatever is faster and more intuitive.
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