PHP is_callable with Type Definitions(PHP is_callable with Type Definitions)

 一直在搜索PHP文档，这似乎不可能，但想检查。 
 
 说我有这样的功能： 
 
class Utils {
  static function doSomething( Array $input ){
    ...
  }
}
 
 是否可以使用像is_callable这样的内置PHP函数来检查函数是否存在以及函数中的类型定义是否接受我所拥有的变量。 
 
 所以： 
 
$varA = array( 'a', 'b', 'c' );
$varB = 'some string';

$functionToCall = array( 'Utils', 'doSomething' );

is_callable( $functionToCall, $varA ) => true;
is_callable( $functionToCall, $varB ) => false;
 
 当然is_callable不能像这样使用。 但是可以在不使用Try Catch的情况下完成吗？ 
 
 如果不是这将是最好的方式吗？ 
 
try {
  Utils::doSomething( 10 )
} catch (TypeError $e) {
  // react here
}
 
 谢谢！ 

Been searching the PHP documentation and this doesn't seem possible but wanted to check.
 
Say I have a function like this:
 
class Utils {
  static function doSomething( Array $input ){
    ...
  }
}
 
Is is possible to use a inbuilt PHP function like is_callable to check if both the function exists and if the variable I have will be accepted by the type definition in the function.
 
So:
 
$varA = array( 'a', 'b', 'c' );
$varB = 'some string';

$functionToCall = array( 'Utils', 'doSomething' );

is_callable( $functionToCall, $varA ) => true;
is_callable( $functionToCall, $varB ) => false;
 
Of course is_callable cannot be used like this. But can it be done without using a Try Catch?
 
If not would this be the best way around it?
 
try {
  Utils::doSomething( 10 )
} catch (TypeError $e) {
  // react here
}
 
Thanks!

原文：https://stackoverflow.com/questions/38916981