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Node.js所有请求的静态头(Node.js static header for all requests)

我想在node.js服务器中为所有传入请求设置静态头。 我目前的方法是为每个请求添加相同的4行标题(代码重复),我想解决这个问题,这里是我要添加的标题的一个示例:

app.post('/postJob', function(req,res){
    console.log("request method :" + req.method);
    // Website you wish to allow to connect
    res.setHeader('Access-Control-Allow-Origin', '*');

    // Request methods you wish to allow
    res.setHeader('Access-Control-Allow-Methods', 'GET, POST, OPTIONS, PUT, PATCH, DELETE');

    // Request headers you wish to allow
    res.setHeader('Access-Control-Allow-Headers', 'X-Requested-With,content-type');

    // Set to true if you need the website to include cookies in the requests sent
    // to the API (e.g. in case you use sessions)
    res.setHeader('Access-Control-Allow-Credentials', true);
    res.setHeader('Content-Type', 'application/json');

有人知道定义它的方法吗?


I want to set a static header for all incoming request in my node.js server. My current way is to add for each request the same 4 lines of header(code duplication) and i want to fix that, here is one example of the header i want to add :

app.post('/postJob', function(req,res){
    console.log("request method :" + req.method);
    // Website you wish to allow to connect
    res.setHeader('Access-Control-Allow-Origin', '*');

    // Request methods you wish to allow
    res.setHeader('Access-Control-Allow-Methods', 'GET, POST, OPTIONS, PUT, PATCH, DELETE');

    // Request headers you wish to allow
    res.setHeader('Access-Control-Allow-Headers', 'X-Requested-With,content-type');

    // Set to true if you need the website to include cookies in the requests sent
    // to the API (e.g. in case you use sessions)
    res.setHeader('Access-Control-Allow-Credentials', true);
    res.setHeader('Content-Type', 'application/json');

Someone knows a way to define that ?


原文:https://stackoverflow.com/questions/29058987
更新时间:2019-10-09 20:14

最满意答案

如果你的程序没有事件循环,你必须调用dispatch_main()

int main(int argc, char **argv)
{
    dispatch_async(dispatch_get_global_queue(DISPATCH_QUEUE_PRIORITY_DEFAULT,0), ^{
        printf("Done outer async\n");
        dispatch_async(dispatch_get_main_queue(),^{
            printf("Done inner sync");
        });
    });

    dispatch_main();
    return 0;
}

从文档:

该函数“停放”主线程并等待块被提交到主队列。 在主线程上调用UIApplicationMain (iOS), NSApplicationMain (Mac OS X)或CFRunLoopRun应用程序不得调用dispatch_main


You have to call dispatch_main() if your program does not have an event loop:

int main(int argc, char **argv)
{
    dispatch_async(dispatch_get_global_queue(DISPATCH_QUEUE_PRIORITY_DEFAULT,0), ^{
        printf("Done outer async\n");
        dispatch_async(dispatch_get_main_queue(),^{
            printf("Done inner sync");
        });
    });

    dispatch_main();
    return 0;
}

From the documentation:

This function "parks" the main thread and waits for blocks to be submitted to the main queue. Applications that call UIApplicationMain (iOS), NSApplicationMain (Mac OS X), or CFRunLoopRun on the main thread must not call dispatch_main.

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