.NET中单向同步的可扩展解决方案有哪些？(What are the extensible solutions for one-way sync in .NET?)

 
 
 您没有正确使用$.each() 。 尝试这个： 
 $ .each（$（'[id $ =“ - subtotal”]'），function（key，element）{subtotal = some_math; 
 id = some_ID_Number; data ['id-'+ String（id）] = subtotal}）; 
 
 
 
 
 
 您应该将data声明为对象，而不是数组。 数组只能有数字键。 对象可以包含包含其他字符的键。 如果是console.log(data)您将看到数据如果是对象则将包含数据，如果初始化为数组，则将为空。 所以试试这个： 
 
 
 
 
 
 
  
  var data = {};

  $.each($('*'), function() {
    subtotal = Math.random() * 100;
    id = Math.random() * 100;
    data['id-' + String(id)] = subtotal
  });

  console.log(data);
 
  
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
 
 
 
 

 
 
You are not using $.each() correctly. Try this:
 
$.each($('[id$="-subtotal"]'), function (key, element) { subtotal = some_math;
 id = some_ID_Number; data['id-' + String(id)] = subtotal });
 
 
 
 
 
You should declare data as an object, not an array. An array can only have numeric keys. An object can have keys that contain other characters. If you console.log(data) you will see that data will contain data if it's an object, and will be empty if initialized as an array. So try this:
 
 
 
 
 
 
  
  var data = {};

  $.each($('*'), function() {
    subtotal = Math.random() * 100;
    id = Math.random() * 100;
    data['id-' + String(id)] = subtotal
  });

  console.log(data);
 
  
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>