matlab代码为黄金比例持续分数(matlab code for golden ratio continued fraction)
我正在尝试编写一个Matlab函数来计算有多少项m,它需要黄金分数达到n位精度。 这是我到目前为止,但我一直得到0的输出。
phi = (1+sqrt(5))/2; p=1; p=[1+1/p]; LoopCounter = 0; while (phi-p)>10^(-n) p=[1+1/p]; LoopCounter = LoopCounter + 1; end m=LoopCounter; m
我认为这对于那些研究数论或者刚刚开始学习Matlab的人来说是个常见问题。 任何建议? 谢谢!
I'm trying to write a Matlab function that computes how many terms, m, it takes the golden fraction to get to n digits of accuracy. Here is what I have so far, but I keep getting an output of 0.
phi = (1+sqrt(5))/2; p=1; p=[1+1/p]; LoopCounter = 0; while (phi-p)>10^(-n) p=[1+1/p]; LoopCounter = LoopCounter + 1; end m=LoopCounter; m
I think this is a common question for those studying Number Theory or just starting to learn Matlab. Any advice? Thanks!
原文:https://stackoverflow.com/questions/22000851
更新时间:2024-05-02 20:05
最满意答案
尝试:
public Cursor getBarcodeInfo(String number){ // Safe check to make sure db and number is not null if(db == null || number == null){ return null; } return db.rawQuery("select _id, barcode_item_name, barcode_measurement, barcode_unit from barcode where barcode_number = ?", new String[]{number}); }
try:
public Cursor getBarcodeInfo(String number){ // Safe check to make sure db and number is not null if(db == null || number == null){ return null; } return db.rawQuery("select _id, barcode_item_name, barcode_measurement, barcode_unit from barcode where barcode_number = ?", new String[]{number}); }
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