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将MarkLogic XML转换为JSON(MarkLogic XML to JSON conversion)

我试图将此XML文件转换为JSON但无法取得任何成功。 我的XML中有两个子元素,但它只返回最后一个元素。 如何获取JSON格式的记录?

XML

 <Carousel>
  <Video>
    <Title>1</Title>
    <Abstract>3</Abstract>
    <FileName type="custom" mediatype="image">D</FileName>
    <HasAccess>4</HasAccess>
  </Video>
  <Video>
    <Title>1</Title>
    <Abstract>2</Abstract>
    <FileName type="custom" mediatype="image">D</FileName>
    <HasAccess>3</HasAccess>
  </Video>
</Carousel>

XQUERY:

import module namespace json = "http://marklogic.com/xdmp/json"  at "/MarkLogic/json/json.xqy";

let $custom := let $config := json:config("custom")
           return 
             (
              map:put( $config, "whitespace", "ignore" ),

              $config
             )
let $XML := $XMLFile (: XML content :)
return json:transform-to-json($XML,$custom)

当前输出:

{"Carousel":{"Video":{"Title":"1", "Abstract":"2", "FileName":{"type":"custom", "mediatype":"image", "_value":"D"}, "HasAccess":"3"}}}

我也尝试使用默认的“基本”JSON设置json:transform-to-json($XML)但是得到了错误

XML Element not in expected namespace [http://marklogic.com/xdmp/json/basic] (json:INVALIDELEM): Carousel

它仅在“Full”模式下工作,但它会添加JSON格式的附加信息,如_attribute等,这在我的输出JSON中不是必需的。

请帮助我或者说明为什么它没有以JSON格式返回完整的输出。


I am trying to convert this XML file into JSON but unable to get any success. I have two child element in my XML but it is returning only last one. How to get both the records in JSON format?

XML

 <Carousel>
  <Video>
    <Title>1</Title>
    <Abstract>3</Abstract>
    <FileName type="custom" mediatype="image">D</FileName>
    <HasAccess>4</HasAccess>
  </Video>
  <Video>
    <Title>1</Title>
    <Abstract>2</Abstract>
    <FileName type="custom" mediatype="image">D</FileName>
    <HasAccess>3</HasAccess>
  </Video>
</Carousel>

XQUERY:

import module namespace json = "http://marklogic.com/xdmp/json"  at "/MarkLogic/json/json.xqy";

let $custom := let $config := json:config("custom")
           return 
             (
              map:put( $config, "whitespace", "ignore" ),

              $config
             )
let $XML := $XMLFile (: XML content :)
return json:transform-to-json($XML,$custom)

Current OUTPUT:

{"Carousel":{"Video":{"Title":"1", "Abstract":"2", "FileName":{"type":"custom", "mediatype":"image", "_value":"D"}, "HasAccess":"3"}}}

I also tried it with default "Basic" JSON setting json:transform-to-json($XML) but got error like

XML Element not in expected namespace [http://marklogic.com/xdmp/json/basic] (json:INVALIDELEM): Carousel

It works in "Full" mode only, but it is adding some extra information in JSON format like _attribute etc. which is not required in my output JSON.

Please help me or give any idea why it is not returning complete output in JSON format.


原文:https://stackoverflow.com/questions/26858466
更新时间:2022-12-21 06:12

最满意答案

你的代码基于字符串比较而不是基于数字的排序进行减法。

$(".listitems li").sort(sort_li).appendTo('.listitems');

function sort_li(a, b) {
  // get the diff of `data-position`
  var diff = $(b).data('position') - $(a).data('position');
  // return the difference if it's not 0
  // else return the difference of `data-position2`
  return diff == 0 ? $(b).data('position2') - $(a).data('position2') : diff;
  // although you can use Logical Short-Circuit Evaluation
  // return $(b).data('position') - $(a).data('position') || $(b).data('position2') - $(a).data('position2');
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<ul class="listitems">
  <li data-position="24" data-position2="40500">Item 24 40500</li>
  <li data-position="1" data-position2="90500">Item 1 90500</li>
  <li data-position="0" data-position2="0">Item 0 0</li>
  <li data-position="0" data-position2="0">Item 0 0</li>
  <li data-position="0" data-position2="0">Item 0 0</li>
  <li data-position="3" data-position2="14800">Item 3 14800</li>
  <li data-position="3" data-position2="14801">Item 3 14801</li>
  <li data-position="24" data-position2="40501">Item 24 40501</li>
  <li data-position="24" data-position2="40549">Item 24 40549</li>
</ul>


Your code work based on the string comparison instead do subtraction for number based sorting.

$(".listitems li").sort(sort_li).appendTo('.listitems');

function sort_li(a, b) {
  // get the diff of `data-position`
  var diff = $(b).data('position') - $(a).data('position');
  // return the difference if it's not 0
  // else return the difference of `data-position2`
  return diff == 0 ? $(b).data('position2') - $(a).data('position2') : diff;
  // although you can use Logical Short-Circuit Evaluation
  // return $(b).data('position') - $(a).data('position') || $(b).data('position2') - $(a).data('position2');
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<ul class="listitems">
  <li data-position="24" data-position2="40500">Item 24 40500</li>
  <li data-position="1" data-position2="90500">Item 1 90500</li>
  <li data-position="0" data-position2="0">Item 0 0</li>
  <li data-position="0" data-position2="0">Item 0 0</li>
  <li data-position="0" data-position2="0">Item 0 0</li>
  <li data-position="3" data-position2="14800">Item 3 14800</li>
  <li data-position="3" data-position2="14801">Item 3 14801</li>
  <li data-position="24" data-position2="40501">Item 24 40501</li>
  <li data-position="24" data-position2="40549">Item 24 40549</li>
</ul>

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