Lua，WOW和“......”(Lua, WOW and “…”)

 有几种不同的方法可以构建一行具有可变列数的输出。 哪一个最好可能取决于你在更大范围内实际做了什么。 
 
 一种简单的方法是循环遍历列值并对每个值进行print调用，并将关键字 - 仅参数end设置为换行符之外的其他值。 这将导致它在打印输出结束时跳过通常的换行符。 要在行尾添加换行符，您需要在print()完所有列后进行常规print()调用。 
 
 另一种选择是为您的列构建一个单独的字符串，可能使用str.join 。 根据你想要格式化的东西，这可能是" ".format(str(x) for x in years)或者更复杂的东西。 
 
 这是两个代码： 
 
years = range(min_time, max_time + 1, increment_time)

for year in years:
    print(year, end=" ") # prints a space after each value, rather than a newline
print() # add a newline at the end of the row

row_str = " ".join(str(year) for year in years) # join year strings with spaces
print(row_str) # prints whole row in one step, with a newline at the end

There are a couple different ways that you can build a row of output with a variable number of columns. Which one will be best may depend on what you're actually doing on a larger scale.
 
One simple approach is to loop over your column values and make a print call for each one with the keyword-only argument end set to something other than a newline. This will cause it to skip the usual newline at the end of the printed output. To get a newline at the end of the row, you'll need to make a regular print() call after all the columns have been printed.
 
Another option is to build a single string for your column, probably with str.join. Depending on how you want to format things, this might be " ".format(str(x) for x in years) or maybe something more complicated.
 
Here's code with both of those:
 
years = range(min_time, max_time + 1, increment_time)

for year in years:
    print(year, end=" ") # prints a space after each value, rather than a newline
print() # add a newline at the end of the row

row_str = " ".join(str(year) for year in years) # join year strings with spaces
print(row_str) # prints whole row in one step, with a newline at the end