首页 \ 问答 \ lock()类型转换是否安全?(Is lock() type-cast safe?)

lock()类型转换是否安全?(Is lock() type-cast safe?)

public class A { }
public class B:A { }

void foo()
{
   A a = new B();
   B b = a as B;
}

对于给定的实例设置,将lock(a)等同于lock(b)

我的意思是,锁定是互斥的吗? 如果我在一个线程中lock(b)在另一个线程中lock(b) ,我是否会获得对之前创建的B单个实例的互斥访问?


public class A { }
public class B:A { }

void foo()
{
   A a = new B();
   B b = a as B;
}

for a given instance setup, will lock(a) be equivalent to lock(b) ?

I mean, will locking be mutually exclusive? If I lock(a) in one thread and lock(b) in another thread, will I get a mutually exclusive access to that single instance of B created earlier?


原文:https://stackoverflow.com/questions/2838814
更新时间:2023-09-05 21:09

最满意答案

首先你错过了return ,然后你必须返回一个元素。 在这里返回<p>TextNode

此外,您需要提供一个唯一的密钥。

试试这个:

{this.props.data.productSpecs.map(function(productSpec, i){
        return <span key={i}><b>Category Name:</b> {productSpec}</span>;
})}

First you missed to return, then you must return ONE element. Here you return a <p> and a TextNode

Moreover you need to provide a unique key.

Try with this :

{this.props.data.productSpecs.map(function(productSpec, i){
        return <span key={i}><b>Category Name:</b> {productSpec}</span>;
})}

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