连接多个缓冲区的有效方法(An effective way to concatenate multiple buffers)

 我需要设计一个有两个主要功能的高效 可读类： 
 
 
 
 add_buffer(char* buffer) - 添加一个缓冲区。 
 
 
 char* read_all() - 获取一个大缓冲区，其中包含用户直到现在添加的所有缓冲区（按顺序）。 
 
 
 例如： 
 
char first_buffer[] = {1,2,3};
char second_buffer[] = {4,5,6};

MyClass instance;
instance.add_buffer(first_buffer);
instance.add_buffer(second_buffer);
char* big_buffer = instance.read_all(); // big_buffer = [1,2,3,4,5,6]
 
 注意 ：这个问题有很多解决方案，但我正在寻找一个高效的解决方案，因为在现实生活中，缓冲区会很多很大，我想保存大量的复制和重新分配（比如std :: vector一样）。 我也想要一个可读的c ++代码。 
 
 注意 ：现实生活中的问题是：我正在以分开的块读取来自HTTP请求的数据。 所有块到达后，我想将整个数据返回给用户。 

I need to design an efficient and readable class with 2 main functions:
 
 
 
add_buffer(char* buffer) - add a buffer.
 
 
char* read_all() - get one big buffer that contains all the buffers that the user added until now (by order).
 
 
for example:
 
char first_buffer[] = {1,2,3};
char second_buffer[] = {4,5,6};

MyClass instance;
instance.add_buffer(first_buffer);
instance.add_buffer(second_buffer);
char* big_buffer = instance.read_all(); // big_buffer = [1,2,3,4,5,6]
 
NOTE: There are a lot of solutions for this problem but I'm looking for an efficient one because in real life the buffers will be many and big, and I want to save a lot of copying and reallocs (like what std::vector does). I'm also want a readble c++ code.
 
NOTE: The real life problem is: I'm reading data from an HTTP request that came to me at separated chunks. After all chunks arrived I want to return the whole data to the user.

原文：https://stackoverflow.com/questions/34514098