使用lambda表达式获取属性或类型名称(Using lambda expression to get property OR type name)

 当lambda表达式引用实际实例本身时，如何调整下面的方法？ 
 
 例如，而不是 
 
x => x.Name
 
 表达是 
 
x => x
 
 所以，如果我有一些类“汽车”我可以返回字符串“汽车”，而不是只能操作其属性（例如Car.Colour） 
 
 方法： 
 
public static string GetMemberName(Expression expression)
    {
        if (expression is LambdaExpression)
            expression = ((LambdaExpression)expression).Body;

        if (expression is MemberExpression)
        {
            var memberExpression = (MemberExpression)expression;
            if (memberExpression.Expression.NodeType ==
                ExpressionType.MemberAccess)
            {
                return GetMemberName(memberExpression.Expression)
                       + "."
                       + memberExpression.Member.Name;
            }
            return memberExpression.Member.Name;
        }


        if (expression is UnaryExpression)
        {
            var unaryExpression = (UnaryExpression)expression;

            if (unaryExpression.NodeType != ExpressionType.Convert)
                throw new Exception(string.Format(
                    "Cannot interpret member from {0}",
                    expression));
            return GetMemberName(unaryExpression.Operand);
        }
        throw new Exception(string.Format(
            "Could not determine member from {0}",
            expression));
    }
 
 即我想要的东西： 
 
if (expression is SomeExpressionThatReturnsAnInstance)
{
    return (name of type of instance);
}

How can I adapt the method below to work when the lambda expression refers to the actual instance itself?
 
e.g. instead of
 
x => x.Name
 
the expression is
 
x => x
 
so if I had some class "Car" I could return the string "Car" instead of only being able to operate on its properties (e.g. Car.Colour)
 
The method:
 
public static string GetMemberName(Expression expression)
    {
        if (expression is LambdaExpression)
            expression = ((LambdaExpression)expression).Body;

        if (expression is MemberExpression)
        {
            var memberExpression = (MemberExpression)expression;
            if (memberExpression.Expression.NodeType ==
                ExpressionType.MemberAccess)
            {
                return GetMemberName(memberExpression.Expression)
                       + "."
                       + memberExpression.Member.Name;
            }
            return memberExpression.Member.Name;
        }


        if (expression is UnaryExpression)
        {
            var unaryExpression = (UnaryExpression)expression;

            if (unaryExpression.NodeType != ExpressionType.Convert)
                throw new Exception(string.Format(
                    "Cannot interpret member from {0}",
                    expression));
            return GetMemberName(unaryExpression.Operand);
        }
        throw new Exception(string.Format(
            "Could not determine member from {0}",
            expression));
    }
 
i.e. I want something like:
 
if (expression is SomeExpressionThatReturnsAnInstance)
{
    return (name of type of instance);
}

原文：https://stackoverflow.com/questions/29788448