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从JsonNode获取fieldname(Get fieldname from JsonNode)

我正在用Jackson解析一些json。 这个json的片段如下:

},
"1/1/0": {
  "event": "status",
  "name": "Alarm Status",
  "type": "Alarm",
  "location": "Hall"
},
"1/1/1": {
  "event": "status",
  "name": "Smoke Alarm Status",
  "type": "Alarm",
  "location": "Hall"
},

我很高兴能够为每个'对象'提取数据,但我很难获得每个对象的'名称'。 在上面的例子中,这将是'1/1/0'和'1/1/1'。 我这样做的方式如下:

final JsonNode node = parser.parseToNode(configJson);
final JsonNode sensorsChild = node.get("sensors");

    for (JsonNode root : sensorsChild) {
                    final String event = root.get("event").asText();
                    final String name = root.get("name").asText();
                    final String type = root.get("type").asText();
                    final String location = root.get("location").asText();
    }

我想要for循环中的另一行,如下所示:

final String id = root.getNodeFieldName();

这将分别产生'1/1/0'和'1/1/1'。 谢谢


I am using Jackson to parse some json. An snippet from this json is as follows:

},
"1/1/0": {
  "event": "status",
  "name": "Alarm Status",
  "type": "Alarm",
  "location": "Hall"
},
"1/1/1": {
  "event": "status",
  "name": "Smoke Alarm Status",
  "type": "Alarm",
  "location": "Hall"
},

I've happily managed to extract the data for each 'object', but I am struggling to obtain the 'name' for each object. In the example above, this would be '1/1/0' and '1/1/1'. I do so in the following way:

final JsonNode node = parser.parseToNode(configJson);
final JsonNode sensorsChild = node.get("sensors");

    for (JsonNode root : sensorsChild) {
                    final String event = root.get("event").asText();
                    final String name = root.get("name").asText();
                    final String type = root.get("type").asText();
                    final String location = root.get("location").asText();
    }

I want another line in the the for loop which is something like:

final String id = root.getNodeFieldName();

which would yield '1/1/0' and '1/1/1' respectively. Thanks


原文:https://stackoverflow.com/questions/40365334
更新时间:2023-06-11 20:06

最满意答案

只需在列表解析中使用嵌套循环:

sent = [word for line in f for word in line.lower().split()]

这种方法有一些替代方法,例如使用itertools.chain.from_iterable() ,但我认为在这种情况下嵌套循环更容易。


Just use a nested loop inside the list comprehension:

sent = [word for line in f for word in line.lower().split()]

There are some alternatives to this approach, for example using itertools.chain.from_iterable(), but I think the nested loop is much easier in this case.

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