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jQuery UI多重排序列：滚动问题(jQuery UI multiple sortable columns : issue with scrolling)

 jQuery：1.9.1  
 jQuery UI：1.10.1  
 请看小提琴  
            <td class="my-column" >
                <div id="my-div1" class="my-div-class">
                    <p class="para-item"> para 101 </p>
                </div>
            </td>
            <td>
                <div id="my-div1" class="my-div-class">
                    <p class="para-item"> para 201 </p>
                </div>
            </td>

<script>
    $(".my-div-class").sortable( { connectWith: '.my-div-class' } );
</script>
 
 在小提琴中，当用户尝试将列表1中的顶部项目拖动到列表2的底部时，列表1的滚动条被移动而不是列表2的滚动条。  
 尝试各种事情，但无法使其正常工作。 任何输入/建议都非常感谢。  
 谢谢，拉克什 

jQuery : 1.9.1 
jQuery UI : 1.10.1 
Please See The Fiddle 
            <td class="my-column" >
                <div id="my-div1" class="my-div-class">
                    <p class="para-item"> para 101 </p>
                </div>
            </td>
            <td>
                <div id="my-div1" class="my-div-class">
                    <p class="para-item"> para 201 </p>
                </div>
            </td>

<script>
    $(".my-div-class").sortable( { connectWith: '.my-div-class' } );
</script>
 
In the fiddle, when user tries to drag top item in list-1 into bottom of list-2, the scroll bar of list-1 gets moved instead of list-2 scroll bar.  
Tried various things but couldnt make it to work properly. Any inputs/suggestions are much appreciated. 
Thanks, Rakesh

原文：https://stackoverflow.com/questions/16794882

更新时间：2023-07-19 20:07

最满意答案

 尝试一下：  
op <- merge(df1,df2, 
      all.x = TRUE,
      all.y = TRUE) 

op$df1 <- 1*(op$V1 %in% df1$V1)

op$df2 <- 1*(op$V1 %in% df2$V1)

> op
                                                                               V1 df1 df2
1                                                        A0A061ACH4;Q95Q10;Q9U1W6   1   1
2                                                        A0A061ACL3;Q965I6;O76618   1   1
3                                                 A0A061ACR1;Q2XN02;F5GUA3;Q22498   1   1
4                                                           A0A061AJJ3;A0A061AEA8   1   1
5                                                                      A0A061AL01   1   1
6                                                                          C1P641   1   0
7  H2FLH3;H2FLH2;A0A061ACT3;A0A061AE24;Q23551-2;Q23551;Q23551-4;Q23551-3;Q23551-5   1   1
8                                                               Q22501;A0A061AE05   1   1
9                                                                          Q86CZ7   1   1
10                                                                         Q27GQ4   0   1
 
 要么  
library(dplyr)

op <- merge(df1,df2, 
             all.x = TRUE,
             all.y = TRUE) %>% 
        mutate(df1=1*(V1 %in% df1$V1),
               df2=1*(V1 %in% df2$V1))
 
 以下是您的额外问题的答案：  
 - 知道df1和df2有多少行相似？  
sum(df1$V1 %in% df2$V1) 
 
 -df1中存在多少df1？  
sum(!(df1$V1 %in% df2$V1))
 
 -df2中存在多少df2中不存在的df2？  
sum(!(df2$V1 %in% df1$V1))

Try this out: 
op <- merge(df1,df2, 
      all.x = TRUE,
      all.y = TRUE) 

op$df1 <- 1*(op$V1 %in% df1$V1)

op$df2 <- 1*(op$V1 %in% df2$V1)

> op
                                                                               V1 df1 df2
1                                                        A0A061ACH4;Q95Q10;Q9U1W6   1   1
2                                                        A0A061ACL3;Q965I6;O76618   1   1
3                                                 A0A061ACR1;Q2XN02;F5GUA3;Q22498   1   1
4                                                           A0A061AJJ3;A0A061AEA8   1   1
5                                                                      A0A061AL01   1   1
6                                                                          C1P641   1   0
7  H2FLH3;H2FLH2;A0A061ACT3;A0A061AE24;Q23551-2;Q23551;Q23551-4;Q23551-3;Q23551-5   1   1
8                                                               Q22501;A0A061AE05   1   1
9                                                                          Q86CZ7   1   1
10                                                                         Q27GQ4   0   1
 
OR 
library(dplyr)

op <- merge(df1,df2, 
             all.x = TRUE,
             all.y = TRUE) %>% 
        mutate(df1=1*(V1 %in% df1$V1),
               df2=1*(V1 %in% df2$V1))
 
And here are the answers for your extra questions: 
-know how many lines from df1 and df2 are similar?  
sum(df1$V1 %in% df2$V1) 
 
-how many of df1 exist which don't exist in df2?  
sum(!(df1$V1 %in% df2$V1))
 
-how many of df2 exist which don't exist in df1?  
sum(!(df2$V1 %in% df1$V1))

jQuery UI多重排序列：滚动问题(jQuery UI multiple sortable columns : issue with scrolling)

最满意答案

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