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用jquery ajax传递json对象(passing json object with jquery ajax)

试图回到这里的基础知识并通过ajax将JSON对象发送到我的php。 当我收到JSON错误时,我甚至无法访问该部分。 这是jquery代码:

jQuery(".deletebutton").on("click", function() {

        var employees = [
        { "firstName":"John" , "lastName":"Doe" },
        { "firstName":"Anna" , "lastName":"Smith" },
        { "firstName":"Peter" , "lastName": "Jones" }
        ];

        var dataString = JSON.stringify(employees);

        // Lets put our stringified json into a variable for posting
        var postArray = {json:dataString};

        jQuery.ajax({
            type: 'POST',
            url: 'index.php?option=com_recordings&task=deletevideos&format=raw',
            data: postArray,
            dataType: 'json',
            success: function(data){
                if (data == "blah")
                    alert(data);

            }
        });
});

我收到此错误(当我检查errorThrown ):SyntaxError:JSON.parse:意外字符。 我用jsonlint.com查看它是有效的JSON。 我究竟做错了什么?


Trying to go back to basics here and send a JSON object via ajax to my php. I can't even get to that part as I get a JSON error. Here is the jquery code:

jQuery(".deletebutton").on("click", function() {

        var employees = [
        { "firstName":"John" , "lastName":"Doe" },
        { "firstName":"Anna" , "lastName":"Smith" },
        { "firstName":"Peter" , "lastName": "Jones" }
        ];

        var dataString = JSON.stringify(employees);

        // Lets put our stringified json into a variable for posting
        var postArray = {json:dataString};

        jQuery.ajax({
            type: 'POST',
            url: 'index.php?option=com_recordings&task=deletevideos&format=raw',
            data: postArray,
            dataType: 'json',
            success: function(data){
                if (data == "blah")
                    alert(data);

            }
        });
});

I get this error (when I check errorThrown): SyntaxError: JSON.parse: unexpected character. I checked with jsonlint.com that it is valid JSON. What am I doing wrong?


原文:https://stackoverflow.com/questions/14265826
更新时间:2022-04-15 17:04

最满意答案

你可以做以下两件事之一:

  1. 给出一个固定的%宽度并将数学运算为中心:

position:absolute;width:60%;left:20%100%-60% = 40% - > 40% / 2 = 20%

2。 使用position:absolute;text-align:center;定位div position:absolute;text-align:center; ,并给出内部元素position:relative;display:inline-block;


You can do one of two things:

  1. give a fixed % width and do the math to center:

position:absolute;width:60%;left:20% (100%-60% = 40% --> 40% / 2 = 20%)

2 . position the div using position:absolute;text-align:center;, and give the inner elements position:relative;display:inline-block;

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