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从jqgrid中删除拖放的行(Remove dragged and dropped row from jqgrid)

 我有两个jqgrids设置，可以从'master'拖动到'target'网格。 我放入“目标”网格的行不会保存到数据库中，而是具有生成的唯一ID（前缀为“new_”）。 我有一个自定义寻呼机按钮，删除选定的行。 对于已保存的行，事件将从数据库中删除该项并重新加载网格。 这很好用。 但是，当我想删除未保存到数据库的拖动行时，不会删除该行。  
 这是我的按钮功能：  
onClickButton: function () {
                var deleteId = tgtGrid.getRowData(tgtGrid.getGridParam('selrow'))['ID'];
                if (!deleteId) {
                    return false;
                }
                // remove an added row, not saved in DB
                if (deleteId.indexOf('new_') != -1) {
                    tgtGrid.jqGrid('delRowData', deleteId);
                } else {
                    // remove account saved in DB
                    $.post( url, { id: deleteId }, function (responseData) {
                        if (!responseData.success) {
                            // error here
                        } else {
                           // success here
                           tgtGrid.trigger('reloadGrid');
                        }
                    });
                }

            }
 
 如果我设置按钮在保存的行tgtGrid.jqGrid('delRowData', deleteId);上使用'delRowData' tgtGrid.jqGrid('delRowData', deleteId); 它返回true并从网格中删除行（不是DB，如预期的那样）。  
 如何删除掉落的行？ 

I have two jqgrids setup and can drag from 'master' to 'target' grids. The row I drop into the 'target' grid is not saved to the database and has a generated, unique ID (prefixed with "new_"). I have a custom pager button that deletes the selected row. For saved rows, the event deletes the item from the database and reloads the grid. This works fine. However when I want to remove a dragged row that is NOT saved to the DB the row is not removed. 
Here is my button function: 
onClickButton: function () {
                var deleteId = tgtGrid.getRowData(tgtGrid.getGridParam('selrow'))['ID'];
                if (!deleteId) {
                    return false;
                }
                // remove an added row, not saved in DB
                if (deleteId.indexOf('new_') != -1) {
                    tgtGrid.jqGrid('delRowData', deleteId);
                } else {
                    // remove account saved in DB
                    $.post( url, { id: deleteId }, function (responseData) {
                        if (!responseData.success) {
                            // error here
                        } else {
                           // success here
                           tgtGrid.trigger('reloadGrid');
                        }
                    });
                }

            }
 
If I set up the button to use 'delRowData' on the saved row tgtGrid.jqGrid('delRowData', deleteId); it returns true and the row is removed from the grid (not the DB, as expected). 
How do I remove a dropped row?

原文：https://stackoverflow.com/questions/26638982

更新时间：2022-10-17 18:10

最满意答案

 你有没有对jar文件的控制权？ 如果您创建它未压缩，那可能会更快。 显然它会使jar文件更大，但...  
 还有一件事要检查 - 你如何提取文件？ 例如，如果你逐字节地做，它将会非常缓慢。 使用这样的东西：  
public static void copyStream(InputStream input, OutputStream output)
     throws IOException
{
    // Reads up to 8K at a time. Try varying this.
    byte[] buffer = new byte[8192];
    int read;

    while ((read = input.read(buffer)) != -1)
    {
        output.write(buffer, 0, read);
    }
}
 
 如果你已经这样做了，你能给我们提供更多的信息吗？ “有点慢”有多慢？ 比如说，如何使用jar实用程序来提取jar文件？ 

Do you have control over the jar file? If you create it uncompressed, that may make it faster. Obviously it'll make the jar file bigger though... 
Another thing to check - how are you extracting the file? For instance, if you're doing it byte by byte it will be painfully slow. Use something like this: 
public static void copyStream(InputStream input, OutputStream output)
     throws IOException
{
    // Reads up to 8K at a time. Try varying this.
    byte[] buffer = new byte[8192];
    int read;

    while ((read = input.read(buffer)) != -1)
    {
        output.write(buffer, 0, read);
    }
}
 
If you're already doing this, could you give us more information? How slow is "somewhat slow"? How does it compare with, say, using the jar utility to extract the jar file?

从jqgrid中删除拖放的行(Remove dragged and dropped row from jqgrid)

最满意答案

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