首页 \ 问答 \ 在Java中,`synchronized`等同于`synchronized(this)`?(In Java, is `synchronized` equivalent to `synchronized (this)`?)

在Java中,`synchronized`等同于`synchronized(this)`?(In Java, is `synchronized` equivalent to `synchronized (this)`?)

我正在查看DatagramSocket的源代码,我发现了这个:

public void disconnect() {
    synchronized (this) {
        if (isClosed())
            return;
        if (connectState == ST_CONNECTED) {
            impl.disconnect ();
        }
        connectedAddress = null;
        connectedPort = -1;
        connectState = ST_NOT_CONNECTED;
    }
}

我对同步方法的理解是他们锁定了this 。 那么代码是否等同于以下内容?

public synchronized void disconnect() {
    if (isClosed())
        return;
    if (connectState == ST_CONNECTED) {
        impl.disconnect ();
    }
    connectedAddress = null;
    connectedPort = -1;
    connectState = ST_NOT_CONNECTED;
}

语言设计者选择不在此使用同步方法是否有原因?


I was looking through the source code for DatagramSocket and I found this:

public void disconnect() {
    synchronized (this) {
        if (isClosed())
            return;
        if (connectState == ST_CONNECTED) {
            impl.disconnect ();
        }
        connectedAddress = null;
        connectedPort = -1;
        connectState = ST_NOT_CONNECTED;
    }
}

My understanding of synchronized methods is that they lock on this. So is the code equivalent to the following?

public synchronized void disconnect() {
    if (isClosed())
        return;
    if (connectState == ST_CONNECTED) {
        impl.disconnect ();
    }
    connectedAddress = null;
    connectedPort = -1;
    connectState = ST_NOT_CONNECTED;
}

Is there a reason why the language designers chose not to use a synchronized method here?


原文:https://stackoverflow.com/questions/32474815
更新时间:2023-10-25 12:10

最满意答案

那么,您希望所有@likers都是喜欢current_user items所有人吗?

@likers = current_user.items.map(&:likes).flatten.map(&:user).flatten.uniq

我添加了uniq所以如果用户喜欢这些帖子中的多个,你就不会看到它们多次出现。 当然,如果你想要重复,你可以省略它。

我也根据您之前的问题对您的其他型号进行了一些猜测,因此您可能需要根据实际实施进行调整。


So, you want all @likers to be all the people who like the current_user's items?

@likers = current_user.items.map(&:likes).flatten.map(&:user).flatten.uniq

I've added the uniq so if a user likes more than one of these posts, you won't see them turn up multiple times. You can omit that, of course, if you want duplicates.

I'm also making some guesses about your other models based on your previous question, so you might need to tweak it depending on your actual implementation.

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