可以在Java中简化此并发代码(Can this concurrent code be simplified in Java)

 我有以下用例：我的Android应用程序向服务器发出多个并发HTTP请求。 如果请求产生“不正确的令牌”错误，则应用程序应通过向服务器发出特殊请求并重复失败的请求来重新生成令牌。 
 
 因为有多个并发请求产生相同的错误，所以只有在使用以下构造时才应生成令牌： 
 
static final AtomicBoolean isTokenSync = new AtomicBoolean(false);
private static CountDownLatch countDownLatchTokenSync;

if (isTokenSync.compareAndSet(false, true)) {
        countDownLatchTokenSync = new CountDownLatch(1);

        generateAndSaveToken(...);

        isTokenSync.set(false);   
        countDownLatch.countDown();
    }
    else {
        try {
            countDownLatch.await(5, TimeUnit.MINUTES);
        } catch (InterruptedException e) {
        }
    }
}

// repeat the request
 
 基本上，第一个线程通过并生成令牌，其他线程等待，直到令牌生成并继续。 我的代码是实现这种行为的好方法吗？ 可以简化吗？ 

I have the following use case: my Android application makes multiple concurrent HTTP requests to the server. If a request produces "Incorrect token" error then the application should regenerate the token by making a special request to the server and repeat the failed request. 
 
As there are multiple concurrent requests that produce the same error and token should be generated only once I used the following construct:
 
static final AtomicBoolean isTokenSync = new AtomicBoolean(false);
private static CountDownLatch countDownLatchTokenSync;

if (isTokenSync.compareAndSet(false, true)) {
        countDownLatchTokenSync = new CountDownLatch(1);

        generateAndSaveToken(...);

        isTokenSync.set(false);   
        countDownLatch.countDown();
    }
    else {
        try {
            countDownLatch.await(5, TimeUnit.MINUTES);
        } catch (InterruptedException e) {
        }
    }
}

// repeat the request
 
Basically first thread gets through and generates the token and other threads wait until token generated and proceed. Is my code a good approach to achieve the behavior? Can it be simplified? 

原文：https://stackoverflow.com/questions/33831419