首页 \ 问答 \ Java compareTo一步一步执行(Java compareTo step by step execution)

Java compareTo一步一步执行(Java compareTo step by step execution)

我基本了解Java compareTo方法按lexicographically compares两个字符串。 我在这里阅读了基础知识Java中的字符串比较

我有以下示例:

public class CompareTo {
   public static void main(String args[]) {
       String str1 = "String";
       String str2 = "compareTo";
       String str3 = "String";
       int var1 = str1.compareTo( str2 );
       System.out.println("str1 & str2 comparison: "+var1);

       int var2 = str1.compareTo( str3 );
       System.out.println("str1 & str3 comparison: "+var2);
   }
}

我得到var1 = -16var2 = 0

如果有人一步一步地向我解释这个Lexicographic comparison ,那将会有很大的帮助。

谢谢。


I have basic understanding that Java compareTo method lexicographically compares two strings. I have read basics here String Comparison in Java

I have following example:

public class CompareTo {
   public static void main(String args[]) {
       String str1 = "String";
       String str2 = "compareTo";
       String str3 = "String";
       int var1 = str1.compareTo( str2 );
       System.out.println("str1 & str2 comparison: "+var1);

       int var2 = str1.compareTo( str3 );
       System.out.println("str1 & str3 comparison: "+var2);
   }
}

I get var1 = -16 and var2 = 0.

If someone explains me this Lexicographic comparison step by step It would be of great help.

Thanks.

更新时间:2022-09-09 13:09

最满意答案

根据文档 ,有一个String GetString (Int32 id)函数。 您需要使用getResources()从应用程序上下文中获取Resources实例,然后您可以调用该方法。


According to the docs, there is a String GetString (Int32 id) function. You need to get a Resources instance from the application context, using getResources(), then you can call the method.

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