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Jackson Json访问JsonNode属性名称(Jackson Json accesing JsonNode property name)

 我有这样的架构：  
{
  "type" : "object",
  "$schema" : "http://json-schema.org/draft-03/schema#",
  "id" : "urn:jsonschema:com:vlashel:dto:UserDto",
  "description" : "this is the top description",
  "title" : "this is the top title",
  "properties" : {
    "number" : {
      "type" : "integer"
      "required" : true
    },
    "password" : {
      "type" : "string"
      "required" : true

    }
}
 
 我有以下代码通过删除“required”将此shcema draft 3转换为draft 4，我想收集其中包含'requred'的节点属性名称。 我怎么做？ 我没有看到这方面的方法..  
             JsonNode jsonNode = jsonNodeIterator.next();
            ObjectNode element;
            if (jsonNode instanceof ObjectNode) {
                element = (ObjectNode) jsonNode;
                element.remove("required");
               String propertyName = element.getPropertyName(); //I'm looking for this kind of method.
 
 谢谢！ 

I have a schema like this: 
{
  "type" : "object",
  "$schema" : "http://json-schema.org/draft-03/schema#",
  "id" : "urn:jsonschema:com:vlashel:dto:UserDto",
  "description" : "this is the top description",
  "title" : "this is the top title",
  "properties" : {
    "number" : {
      "type" : "integer"
      "required" : true
    },
    "password" : {
      "type" : "string"
      "required" : true

    }
}
 
I have the following code that converts this shcema draft 3 to draft 4 by removing "required", I want to collect nodes property names that have 'requred' in them. How do I do that? I don't see methods for this.. 
             JsonNode jsonNode = jsonNodeIterator.next();
            ObjectNode element;
            if (jsonNode instanceof ObjectNode) {
                element = (ObjectNode) jsonNode;
                element.remove("required");
               String propertyName = element.getPropertyName(); //I'm looking for this kind of method.
 
Thanks!

原文：https://stackoverflow.com/questions/26108156

更新时间：2022-12-10 15:12

最满意答案

 您不必使用foreach迭代对象，因为'age'是$data->faceAttributes一个属性。  
 改用它  
if (count($data->faceAttributes)) {    
    echo $data->faceAttributes->age;
    echo $data->faceAttributes->gender;
}
 
 但是， $data是一个数组，您使用的$data[0]实际上是$data[0]  
 所以，如果数据数组中只有一个元素，你可以这样做  
$data = $data[0] or $data = json_decode($json)[0]
 
 或者，如果多于一个元素，则可以遍历$data 。 

You don't have to iterate the object using foreach as the 'age' is a property of $data->faceAttributes itself. 
Use this instead  
if (count($data->faceAttributes)) {    
    echo $data->faceAttributes->age;
    echo $data->faceAttributes->gender;
}
 
However, $data is an array and which $data you are using is actually $data[0] 
So, if there is only one element in data array you can do  
$data = $data[0] or $data = json_decode($json)[0]
 
Or, you can iterate through $data in case of more then one element.

Jackson Json访问JsonNode属性名称(Jackson Json accesing JsonNode property name)

最满意答案

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