IPAD 2卡住了怎么办 急==========

 基本思想是你的HandleUnauthorizedRequest方法需要为处理登录的页面/控制器提供“返回”参数。 而不是将您的用户发送到登录页面： 
 
LogOnUrl = urlHelper.Action("LogIn", "Account")
 
 您将提供额外的returnUrl查询参数： 
 
// for your ajax
LogOnUrl = urlHelper.Action("LogIn", "Account", new { returnUrl = context.HttpContext.Request.RawUrl })

// for your non-ajax:
context.Result = new RedirectToRouteResult(
                new System.Web.Routing.RouteValueDictionary
                    {                     
                            { "controller", "Account" },
                            { "action", "Login" },
                            { "returnUrl", context.HttpContext.Request.RawUrl }
                    });
 
 用户将登陆以下页面： 
 
warheat1990.com/login?returnUrl=warheat1990.com%2Farticles%2Fbatman-arkham-knight-review
 
 如果登录成功，那么您将解析查询param returnUrl值的请求（如果存在），并将用户重定向到该位置。 

The basic idea is that your HandleUnauthorizedRequest method needs to provide a "return to" parameter to the page/controller handling the login. Instead of sending your user to just the login page:
 
LogOnUrl = urlHelper.Action("LogIn", "Account")
 
You would provide an additional returnUrl query param:
 
// for your ajax
LogOnUrl = urlHelper.Action("LogIn", "Account", new { returnUrl = context.HttpContext.Request.RawUrl })

// for your non-ajax:
context.Result = new RedirectToRouteResult(
                new System.Web.Routing.RouteValueDictionary
                    {                     
                            { "controller", "Account" },
                            { "action", "Login" },
                            { "returnUrl", context.HttpContext.Request.RawUrl }
                    });
 
The user would land on a page like:
 
warheat1990.com/login?returnUrl=warheat1990.com%2Farticles%2Fbatman-arkham-knight-review
 
If login succeeds, then you would parse the request for the query param returnUrl value (if it exists), and redirect the user to that location.