IOS上的JQuery很慢，跳跃和生涩(JQuery on IOS is slow, jumpy and jerky)

 我正在使用3D坐标来考虑 
 
 
 
 由矢量翻译[uv] 
 
 
 由matrixabcd进行二维线性变换 
 
 
 整体变换矩阵将具有这种形式 
 
    [ a b u]
M = [ c d v]
    [ 0 0 1]
 
 
 
 从三角形取3点A=[x1 y1 1]和B=[x2 y2 1] ， C=[x3 y3 1] 
 
 
 将它们与它们在变换A' = [x1' y1' 1]和B'=[x2' y2' 1]并且C'=[x3' y3' 1] 。 Id est：用数学方法得到变换矩阵M使A' = MA和B' = MB ， C' = MC 
 
 
 将x -> M x应用于每个输入点 
 
 
 编辑：使用转换矩阵中的翻译将翻译合并到矩阵M 中 
 
 编辑：看起来“做你的数学”并不清楚你。 
 
 你会意识到3个方程可以写成： 
 
[x1' x2' x3']     [x1 x2 x3]
[y1' y2' y3'] = M [y1 y2 y3]
[1   1   1  ]     [1  1  1 ]
 
 要么 
 
X' = M X
 
 要么 
 
M = X . X'^-1
 
 是的，OpenCV在矩阵上有一个函数inv() 。 

I'm using 3D coordinates to take account
 
 
 
translation by vector [u v]
 
 
2D linear transformation made by matrixabcd
 
 
The overall transformation matrix will have the form
 
    [ a b u]
M = [ c d v]
    [ 0 0 1]
 
 
 
Take 3 points A=[x1 y1 1] and B=[x2 y2 1] and C=[x3 y3 1] from the triangle
 
 
Compare them with their position after transformation A' = [x1' y1' 1] and B'=[x2' y2' 1] and C'=[x3' y3' 1]. Id est: Do your math to get the transformation matrix M so that A' = M A and B' = M B and C' = M C
 
 
Apply x -> M x to every input points
 
 
Edit: Incorporate the translation in the matrix M using Translation in transformation matrix
 
Edit: It seems "do your math" is not clear for you.
 
You'll realize that the 3 equations can be written as:
 
[x1' x2' x3']     [x1 x2 x3]
[y1' y2' y3'] = M [y1 y2 y3]
[1   1   1  ]     [1  1  1 ]
 
or
 
X' = M X
 
Or
 
M = X . X'^-1
 
and yes, OpenCV has a function inv() on matrices.